Question

我无法在测试功能的第27行找到错误：

var rowValues[column-2] = range.getValues();

我的代码：

var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheets()[0];

var lastRow = sheet.getLastRow();
var lastColumn = sheet.getLastColumn();

var now = new Date();    

function test() {

   for (row = 2; row < lastRow ; row++) {

        range = sheet.getRange(row, 1, 1, 1);  
        dateAdd = range.getValues();

        range = sheet.getRange(row, 5, 1, 1);  
        dateValidation = range.getValues();

        timeDiff = Math.abs(now.getTime() - Date.parse(dateAdd));
        diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24)); 

        if (diffDays==1 &&  dateValidation==""){
            for (column = 2; column < lastColumn ; column++) {
                range = sheet.getRange(row, column, 1, 1);  
                rowValues[column-2] = range.getValues();
            }

          MailApp.sendEmail("xxxx@xxx.xxx","Subject %n","Description:  \n %d \n %d \n %d",row,rowValues[0],rowValues[1],rowValues[3]);
        }

      } 

    }

Answer 1

你已经使用了额外的var，你不应该有一个 - 基本上你已经这样做了：

var array = [];
var array[0] = "foo";

你应该在哪里：

var array = [];
array[0] = "foo";

所以改变你的代码行：

var rowValues[column-2] = range.getValues();

到

rowValues[column-2] = range.getValues();

Answer 2

尝试更新此行：

<强>这里：

    var rowValues[column-2] = range.getValues();

要

rowValues[column-2] = []; rowValues[column-2].push(range.getValues());

Answer 3

我找到了解决方案：

range = sheet.getRange(row, column, 1, 1);  
rowValues.push(range.getValues());

代码中缺少分号

3 个答案: