按表达式

Question

使用角度ng-repeat，如何根据对象数组中的键过滤掉项目？

例如，我有这个数据集：

$scope.data = [
  {
    name: "Example",
    id: 1,
    status: "deleted"
  },
  {
    name: "Example",
    id: 1,
    status: "pending"
  },
  {
    name: "Example",
    id: 1,
    status: "active"
  }
  // etc
]

如何使用status: "deleted"删除项目？

<div ng-repeat="item in data">
   <h1>{{item.name}}</div>
   <p>Status: {{item.status}}</p>
</div>  

Answer 1

以下是如何在ng-repeat中使用过滤器： -

4.32999992370605

var app = angular.module("myApp", []);
app.controller("myCtrl", function($scope) {
  
$scope.data = [
  {
    name: "Example",
    id: 1,
    status: "deleted"
  },
  {
    name: "Example",
    id: 1,
    status: "pending"
  },
  {
    name: "Example",
    id: 1,
    status: "active"
  }
  // etc
]
});

Answer 2

使用SELECT * FROM test WHERE ('engineer' LIKE CONCAT(columnName,'%')) OR ('engineer' LIKE CONCAT(LOWER(columnName),'%')); 检查状态

ng-if

Answer 3

您可以在div中添加ng-if，如

<div ng-repeat="item in data" ng-if="item.status!='deleted'">
   <h1>{{item.name}}</div>
   <p>Status: {{item.status}}</p>
</div>