Question

我正在尝试解析此JSON字符串。但是我一直在NSArray遇到问题。

var tContacts: [String] = []


if let jsonData = data {
                //let jsonObj = try! JSONSerialization.jsonObject(with: jsonData, options: [])
                let jsonObj = try! JSONSerialization.jsonObject(with: jsonData, options: []) as! [String:AnyObject]
                print(jsonObj)



                let rescode = jsonObj["respond"] as! String?
               altogether")


                self.tContacts = jsonObj["mylist"] as! Array  **(ERROR HERE)**
................
...........
......
}

错误：无法投射类型＆＃39; __ NSDictionaryI＆＃39; （0x107b25288）到＆＃39; NSString＆＃39; （0x107130c60）。

["list_id": 1, "respond": success, "mylist": <__NSArrayI 0x618000231b60>(
{
    email = "porkman@live.com";
    name = John;
    status = active;
},
{
    email = "gorillaunderwear@gmail.com";
    name = Gregh;
    status = active;
}
)
]

Answer 1

tContacts是一个String数组，但jsonObj["mylist"]返回Dictionaries数组。您可以将tContacts声明为Any对象的数组

var tContacts: [Any] = []  or
var tContacts:[[String:Any]] = [[:]]

Answer 2

将 var tContacts：[String] = [] 替换为var tContacts: [[String:AnyObject]] = [[String:AnyObject]]()

希望这会对你有帮助......

Xcode iOS：如何解析这个JSON？

2 个答案: