Question

我想触发一个新实体的实例化。 有人可以说是否可能，以及如何？ 等待一个问题，我带来了这个解决方案，在服务中获得一个新的实体...但我发现它没有足够的优化。这是我的代码的简化摘录，附加了一个事件＆＃34; onCreate＆＃34;在听众中：这运行良好，但我必须调用一个新实体，通过一个服务。我希望我的新实体直接填充而只是做＆＃34; $ entity = new entity（）;＆＃34;

abstract class serviceBaseEntity extends serviceBaseClass {

const ENTITY_CLASS = ''; // here class of entity

protected $classname;
protected $shortname;
protected $EntityManager;
protected $ObjectManager;

public function __construct(ContainerInterface $container, RequestStack $request_stack) {
    parent::__construct($container, $request_stack);
    $this->EntityManager = $this->container->get('doctrine.orm.entity_manager');
    $this->ObjectManager = $this->container->get('doctrine')->getManager();
    $this->addEventSubscriber(new serviceAnnotations($container, $request_stack));
    $this->classname = $this->calledClassname::ENTITY_CLASS;
    $this->shortname = (new ReflectionClass($this->classname))->getShortName();
    return $this;
}

protected function addEventSubscriber(EventSubscriber $EventSubscriber) {
    $this->EntityManager->getEventManager()->addEventSubscriber($EventSubscriber);
    return $this;
}

    public function getNew() {
    $entity = new $this->classname;
    $eventArgs = new LifecycleEventArgs($entity, $this->ObjectManager);
    $this->EntityManager->getEventManager()->dispatchEvent(AnnotationsBase::onCreate, $eventArgs);
    return $entity;
}

Answer 1

也许你可以在你的实体中使用一种工厂方法，使用私有构造函数。例如：

Class MyEntity {
    private function __construct( ) {
        your code
    }
    public static function createEntity(your params) {
           do some stuff
           $e=new MyEntity();
           do some other stuff
           return $e;
    }
}

PHP Symfony3，实例化一个新实体的监听器

1 个答案: