Question

我有以下字符串：

"TTTHTHTTHTTTTHTTTHTTTTTTHTTTTTHTH"

我希望能够将T分组列入一个列表，然后将T的数量计入第一个H.

即。

[3, 1, 2, 4, 3, 6, 5, 1]

在python中最有效的方法是什么？

Answer 1

itertools.groupby是你的朋友

from itertools import groupby

s = "TTTHTHTTHTTTTHTTTHTTTTTTHTTTTTHTH"

res = [sum(1 for _ in g) for k, g in groupby(s) if k == 'T']
print(res)

# [3, 1, 2, 4, 3, 6, 5, 1]

Answer 2

您可以使用列表解析在一行中执行此操作：

my_string = "TTTHTHTTHTTTTHTTTHTTTTTTHTTTTTHTH"
my_list = [len(i) for i in my_string.split('H') if len(i)>0]

my_list的输出：

[3, 1, 2, 4, 3, 6, 5, 1]

Answer 3

您可以使用itertools实现此目的：

import itertools
s = "TTTHTHTTHTTTTHTTTHTTTTTTHTTTTTHTH"
counts = []
count = 1
for a, b in zip(s, s[1:]):
    if a==b:
        count += 1
    elif a == "T":
        counts.append(count)
        count = 1

给出：

   counts
=> [3, 1, 2, 4, 3, 6, 5, 1]

Answer 4

另一种使用列表理解的方法：

my_string = "TTTHTHTTHTTTTHTTTHTTTTTTHTTTTTHTH"

strips = my_string.strip('H')
splits = strips.split('H' )

# generating iterables of 1 and then summation 
my_list = [sum(1 for i in j) for j in splits]

print(my_list )

给予

[3, 1, 2, 4, 3, 6, 5, 1]

[Program finished]

按单个字符分组，否则拆分

4 个答案: