Angular TypeError:在尝试调用object.object []时不是函数。方法

时间:2017-08-03 03:59:31

标签: angular function typescript typeerror

当我尝试在角度4中调用object.object []。方法的方法时,我收到以下错误:

  

OrderComponent.html:30 ERROR TypeError:item.increaseQuantity不是a   功能       在OrderComponent.increaseQuantity(order.component.ts:87)

我的打字稿代码如下。当我调用OrderComponent.IncreaseQuantity(itemLoc:number)方法时,当我尝试在方法中调用this.orderItems [itemLoc] .increaseQuantity()方法时,它会生成上面的错误。我不知道为什么它不知道OrderItem.increaseQuantity方法:

import { Component, Inject } from '@angular/core';
import { Http } from '@angular/http';

class OrderItem {
    id: number;
    name: string;
    unitPrice: number;
    quantity: number;
    amount: number;
    comment: string;

    increaseQuantity(): boolean {
        console.log("In the Order Item itself - worked.");
        this.quantity += 1;
        this.amount = this.quantity * this.unitPrice;
        return false;
    }
}

class Order {
    id: number;
    createdTime: Date;
    orderType: string;
    tableName: string;
    orderItems: OrderItem[];
}

@Component({
    selector: 'order',
    templateUrl: './order.component.html'
})
export class OrderComponent {
    public order: Order;
    public total: number = 0;


    constructor(http: Http, @Inject('ORIGIN_URL') originUrl: string) {
        http.get(originUrl + '/api/Order/2').subscribe(result => {
            this.order = result.json() as Order;
            this.updateTotal();
        });

    }

    updateTotal(): void {
        this.total = 0;
        //console.log("all: " + JSON.stringify(this.order.orderItems));
        this.order.orderItems.forEach(s => this.total += s.amount);
    }

    increaseQuantity(itemLoc: number): boolean {
        //item.increaseQuantity();
        let item = this.order.orderItems[itemLoc] as OrderItem;

        console.log("This increaseQuantity work." + JSON.stringify(item));

        return item.increaseQuantity();
        //return false;
    }

}

1 个答案:

答案 0 :(得分:6)

您永远不会实例化任何OrderOrderItem个实例。刚做

this.order = result.json() as Order

let item = this.order.orderItems[itemLoc] as OrderItem;

不会导致自动创建这些实例,因此您最终会在纯数据对象(即从JSON解析的对象)上调用您的方法。这些对象没有定义那些实例方法方法,这会导致您看到的错误。

相反,你必须做类似的事情:

const orderData = result.json();

const order = new Order();
order.id = orderData.id;
// ... assign rest of properties
order.items = orderData.orderItems.map(orderItemData => {
    const orderItem = new OrderItem();
    orderItem.id = orderItemData.id;
    // ... assign rest of properties

    return orderItem;
});

this.order = order;

实用函数,构造函数和接口的创造性使用可以用来使上面更简洁,但实际上这是需要的。