我在ListView中的行中有EditTexts。当我点击其中一个EditTexts时,软键盘出现,焦点跳转到列表中的第一个EditText,而不是停留在我点击的字段中。
以下是视频:
我创建了一个完全剥离的应用程序来演示问题。完整代码位于:https://pastebin.com/YT8rxqKa
我没有做任何事情来改变我的代码中的焦点:
@Override
public View getView(int position, View convertView, ViewGroup parent) {
if (convertView == null) {
convertView = layoutInflater.inflate(R.layout.cell_textfield, parent, false);
}
TextView label = (TextView) convertView.findViewById(R.id.textview1);
EditText textfield = (EditText) convertView.findViewById(R.id.textview2);
String text = String.format("Row %d", position);
label.setText(text);
textfield.setText(text);
return convertView;
}
我发现another post on StackOverflow为这种愚蠢的Android行为提供了一种解决方法,其中包括在所有文本字段上放置一个OnFocusChangedListener,以便在不正确地从它们中取出时可以重新获得焦点。
这有助于重新获得焦点,但随后我发现当文本字段重新聚焦时,光标会在文本的开头而不是结束处结束,这对我的用户来说是不自然的并且很烦人。
以下是视频:
这是OnFocusChangeListener的代码。它可以解决移动焦点的愚蠢Android行为,但是光标在重新获得焦点后会被放错位置。
View.OnFocusChangeListener onFocusChangeListener = new View.OnFocusChangeListener() {
@Override
public void onFocusChange(View view, boolean hasFocus) {
long t = System.currentTimeMillis();
long delta = t - focusTime;
if (hasFocus) { // gained focus
if (delta > minDeltaForReFocus) {
focusTime = t;
focusTarget = view;
}
}
else { // lost focus
if (delta <= minDeltaForReFocus && view == focusTarget) {
focusTarget.post(new Runnable() { // reset focus to target
public void run() {
Log.d("BA", "requesting focus");
focusTarget.requestFocus();
}
});
}
}
}
};
我讨厌在一个绑在一个绑带上绑一个绑带,试图让Android按照自然预期的行为表现,但我会采取我能得到的。
1)我可以做些什么来解决这个问题,而不必使用OnFocusChangeListener吗?
2)如果(1)不可能,那么当我将焦点强制回到正确的字段时,我如何确保将光标放在最后?我在requestFocus()之后尝试使用setSelection()
,但由于文本字段尚未聚焦,因此忽略了选择。
答案 0 :(得分:2)
这是我的解决方案。&#34;简而言之:ListView
是愚蠢的,并且在涉及EditText
时总是一场噩梦,因此我更改了Fragment / Adapter代码以适应ListView
布局或ScrollView
布局。它只适用于行数较少的情况,因为scrollview实现无法利用延迟加载和查看回收。值得庆幸的是,在ListView中我想要EditTexts的任何情况,我很少有超过20行左右。
在BaseListFragment
中夸大我的观点时,我会通过依赖hasTextFields()
方法的方法获取布局ID:
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(getLayoutId(), container, false);
return view;
}
public boolean hasTextfields() {
return false;
}
public int getLayoutId() {
if (hasTextfields()) {
return R.layout.scrollfragment;
} else {
return R.layout.listfragment;
}
}
在我的BaseListFragment
的各个子类中,如果我需要在其中一个字段中有EditText
,我只需覆盖hasTextFields()
方法返回true然后我的片段/适配器切换到使用基本的scrollview实现。
从那里开始,确保适配器处理ListView
和ListView
方案的标准ScrollView
操作是一个问题。像这样:
public void notifyDataSetChanged() {
// If scrollContainer is not null, that means we're in a ScrollView setup
if (this.scrollContainer != null) {
// intentionally not calling super
this.scrollContainer.removeAllViews();
this.setupRows();
} else {
// use the real ListView
super.notifyDataSetChanged();
}
}
public void setupRows() {
for (int i = 0; i < this.getCount(); i++) {
View view = this.getView(i, null, this.scrollContainer);
view.setOnClickListener(myItemClickListener);
this.scrollContainer.addView(view);
}
}
点击侦听器提出的一个问题是ListView需要AdapterView.OnItemClickListener
,但View
内的任意ScrollView
想要一个简单的View.OnClickListener
。所以,我让我的ItemClickListener也实现了View.OnClickListener
,然后只是将OnClick调度到OnItemClick方法:
public class MyItemClickListener implements AdapterView.OnItemClickListener, View.OnClickListener {
@Override
public void onClick(View v) {
// You can either have your Adapter set the tag on the View to be its position
// or you could have your click listener use v.getParent() and iterate through
// the children to find the position. I find its faster and easier to have my
// adapter set the Tag on the view.
int position = v.getTag();
this.onItemClick(null, v, config.getPosition(), 0);
}
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
// ...
}
}
然后在MyEditTextListFragment
中,我创建了这样的适配器:
listener = createClickListener();
adapter = createListAdapter();
if (scrollContainer != null) {
adapter.setScrollContainer(scrollContainer);
adapter.setMenuItemClickListener(listener);
adapter.setupRows();
} else {
getListView().setOnItemClickListener(listener);
getListView().setAdapter(adapter);
}
以下是我的scrollfragment.xml
供参考:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#fff"
android:clickable="true"
>
<!--
The following LinearLayout as a focus catcher that won't cause the keyboard to
show without it, the virtual keyboard shows up immediately/always which means we
never get to the enjoy the full size of our screen while scrolling, and
that sucks.
-->
<LinearLayout
android:focusable="true"
android:focusableInTouchMode="true"
android:layout_width="0px"
android:layout_height="0px"/>
<!--
This ListView is still included in the layout but set to visibility=gone. List
fragments require a standard ListView in the layout, so this gets us past that
check and allows us to use the same adapter code in both listview and scrollview
situations.
-->
<ListView android:id="@id/android:list"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_weight="1"
android:drawSelectorOnTop="false"
android:background="@null"
android:layout_alignParentTop="true"
android:descendantFocusability="afterDescendants"
android:visibility="gone"
/>
<!--
This scrollview will act as our fake listview so that we don't have to deal with
all the stupid crap that comes along with having EditTexts inside a ListView.
-->
<ScrollView
android:id="@+id/scrollView"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:descendantFocusability="afterDescendants"
>
<LinearLayout
android:id="@+id/scrollContainer"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
>
</LinearLayout>
</ScrollView>
</RelativeLayout>
答案 1 :(得分:0)
尝试一次,它对我有用:
public void setCursorPosition() {
focusTarget.requestFocus();
focusTarget.setCursorVisible(true);
other.setCursorVisible(false);
} else {
other.setCursorVisible(true);
focusTarget.setCursorVisible(false);
}
}