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Question

我收到错误消息但不知道如何继续，错误消息显示如下。我已经下载了所有必要的工具供它运行但是它似乎有关键的问题。我已经输入了他们，但为了保持我的帐户私密性，我已经用隐藏的帐户用户名和密码替换了。提前致谢

C:\Users\User\Downloads\real-time-intrinio-python-master\real-time-intrinio-python-master> python realtime.py AAPL 
Using Ticker: AAPL 
Traceback (most recent call last):
  File "realtime.py", line 18, in <module>
     r=requests.get(auth_url, headers={"Authorization": "Basic %s" % base64.b64encode(os.environ['myUsername'] + ":" + os.environ['myPassword'])}) 
  File "C:\Users\User\AppData\Local\Programs\Python\Python36-32\lib\os.py", line 669, in __getitem__
     raise KeyError(key) from None 
KeyError: 'myUsername'

这是我正在使用的代码，第18行是“r = requests.get（auth_url，headers ...”

import websocket
import _thread
import time
import requests
import base64
import json
import sys
import os
from requests.auth import HTTPBasicAuth

try:
    print ("Using Ticker: " + str(sys.argv[1]))
except:
    print ("Please include ticker as first argument")
    sys.exit()

auth_url = "https://realtime.intrinio.com/auth";
r=requests.get(auth_url, headers={"Authorization": "Basic %s" % base64.b64encode(os.environ['7641353c8540cd7c795c96f097185c26'] + ":" + os.environ['c15d32295cf254ab57d5523c5bf95f80'])})

socket_target = "wss://realtime.intrinio.com/socket/websocket?token=%s" % (r.text)

def on_message(ws, message):
    try:
        result = json.loads(message)
        print (result["payload"])
    except:
        print (message)

def on_error(ws, error):
    print ("###ERROR### " + error)

def on_close(ws):
    print ("###CONNECTION CLOSED###")

def on_open(ws):
    def run(*args):
        security = "iex:securities:" + str(sys.argv[1]).upper()
        message = json.dumps({"topic": security,"event": "phx_join","payload": {},"ref": "1"})
        ws.send(message)
    thread.start_new_thread(run, ())


websocket.enableTrace(True)
ws = websocket.WebSocketApp(socket_target, on_message = on_message, on_error = on_error, on_close = on_close)
ws.on_open = on_open
ws.run_forever()