Question

在这个脚本的开头我设置了一些变量（$ numof0 = 3，$ numof1 = 5等）。我想将所有这些变量写入控制台，但我想比下面的10个写主机语句更加简洁。

Write-Host "There are $numOf0 0's"
Write-Host "There are $numOf1 1's"
Write-Host "There are $numOf2 2's"
Write-Host "There are $numOf3 3's"
Write-Host "There are $numOf4 4's"
Write-Host "There are $numOf5 5's"
Write-Host "There are $numOf6 6's"
Write-Host "There are $numOf7 7's"
Write-Host "There are $numOf8 8's"
Write-Host "There are $numOf9 9's"

我认为既然所有变量都有相同的开头（$ numof）并且所有变量都以越来越多的数字结尾，我可以做这样的事情......

$j=0
while($j -lt 10){
    $final = '$numof'+"$j"
    write-host "There are $final $j's"
    $j++
}

显然，变量$ final只是一个字符串，当打印到控制台时，不会显示我想要打印的相应$ numofX变量的内容。

有没有办法使用字符串和另一个变量（字符串'$ numof'和变量'$ j'）创建一个变量（$ final）并仍然引用$ numOfX变量的原始内容？

Answer 1

link可以评估您的字符串，就好像它被键入为命令一样

$j=0
while($j -lt 10){
    $final = Invoke-Expression -Command ('$numof'+"$j")
    write-host "There are $final $j's"
    $j++
}

使用字符串+第二个变量创建变量

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