Question

我用：

json_str = '{"name":"Saeron", "age":23, "score":100}'
def json2dict(d):
    return dict(d['name'],d['age'],d['score'])
d = json.loads(json_str, object_hook=json2dict)
print(d.name)

但是收到错误：

Traceback (most recent call last):
  File "C:/Users/40471/PycharmProjects/untitled/untitled.py", line 693, in <module>
    d = json.loads(json_str, object_hook=json2dict)
  File "C:\Program Files\Python36\lib\json\__init__.py", line 367, in loads
    return cls(**kw).decode(s)
  File "C:\Program Files\Python36\lib\json\decoder.py", line 339, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Program Files\Python36\lib\json\decoder.py", line 355, in raw_decode
    obj, end = self.scan_once(s, idx)
  File "C:/Users/40471/PycharmProjects/untitled/untitled.py", line 692, in json2dict
    return dict(d['name'],d['age'],d['score'])
TypeError: dict expected at most 1 arguments, got 3

我按照指示将Json obj解开为Python obj的步骤，就像这样：

json_str = '{"age": 20, "score": 88, "name": "Bob"}'
print(json.loads(json_str, object_hook=dict2student))

为什么它不会对字典生效？我怎么修改？

Answer 1

使用d = json.loads(json_str)加载json后，d是python dict 你无法使用。（点）。

你需要：

json_str = '{"name":"Saeron", "age":23, "score":100}'
d = json.loads(json_str)
print(d['name'])

Answer 2

json.loads可以直接将您的字符串评估为Python字典，如下所示：

json_str = '{"name":"Saeron", "age":23, "score":100}'
d = json.loads(json_str)
print(d['name'])
>>>Saeron

通过object_hook参数传递的函数将接收从给定字符串创建的字典作为输入

如何将JSON对象转换为Python对象？

2 个答案: