Question

我有一张很大的桌子，我想每年都有一张桌子。我需要用唯一的模型表示多个表。我已经根据年份在不同的表中实现了写入，但我不知道如何使用orm在多个表中读取。有什么建议吗？我正在使用Laravel 5.3

class Management extends Model
{
    protected $table = 'management_2017';

    public function setTableYear($date = null){
        if ( is_null($date) )
            $date = \Carbon::now();
        if ($date->year >= 2017)
            $this->setTable('management_' . $date->year);
    }
}

class MyController extends Controller
{
    public function saveManagement(){
        $management = new Management();
        $management->setTableYear();
        //... set attributes
        $management->save();
    }

    public function readManagement(Request $request){
        $idManagement = $request->get('managementId');
        // I dont know how to set a table here. Default table is 'management_2017'
        $management = Management::find($idManagement);
    }
}

Answer 1

在模型中，您可以创建一个返回查询构建器的方法，其中$ table属性已更新：

class Management extends Model
{
protected $table = 'management_2017';

    public function setTableYear($date = null){
        if ( is_null($date) )
            $date = \Carbon::now();
        if ($date->year >= 2017)
            $this->setTable('management_' . $date->year);
    }

    public static function getInstance()
    {
        $a = new static;
        $a->setTableYear();
        return $a;
    }
}

有了它，你可以在你的控制器中使用它：

class MyController extends Controller
{
    public function readManagement(Request $request){
        $idManagement = $request->get('managementId');
        $management = Management::getInstance()->find($idManagement);
    }
}

如何用唯一的模型表示多个表？

1 个答案: