Question

我有一张桌子：

<div [innerHTML]="the.path.to.property"></div>

现在，我需要找到所有接受过子女教育的父母，即受过教育的孩子=＆＃39;是的。

与上述情况一样，父母＆＃39; P3＆＃39;

任何人都可以建议查询来获取此

Answer 1

select parent, 
       sum(case when educated='YES' then 1 else 0 end) as sum_educated,
       count(*) as count_all
from t
group by parent
having count_all=sum_educated

Answer 2

查找有“No＆＃39; No＆＃39;并使用NOT IN从结果中删除它们：

SELECT parent
FROM table
WHERE parent NOT IN (SELECT parent FROM table WHERE Educated = 'No')
GROUP BY parent

Answer 3

我会这样做：

select parent
from t
group by parent
having max(educated) = min(educated) and max(educated) = 'YES';

如果educated可能是NULL，则逻辑稍微复杂一些。

实际上，如果值只是'YES'或'NO'，您可以做得更简单：

select parent
from t
group by parent
having min(educated) = 'YES';

Answer 4

从[YourTable]中选择* Educated =＆＃39;是＆＃39;

如果您只想显示父列然后从[YourTable]中选择Parent Educated =＆＃39;是＆＃39;

SQL查询组和所有

4 个答案: