Question

我无法将活动广播到特定的房间。

我检查房间里的客户，他们似乎已正确加入房间。

然而socket.broadcast.to(socket.roomChannel).emit("cardSelected", cardInfo) 根本就没有用，

而socket.broadcast.emit("cardSelected", cardInfo)有效（但我只需要向房间广播）。

这让我疯了...... 这是我的代码，不起作用的部分一直到底：

// Setup basic express server
var express = require('express');
var app = express();
var server = require('http').createServer(app);

var io = require('socket.io')(server);
var port = '4000';

server.listen(port, function () {
});

this.rooms = [];

let lastRoomId = 0
let lastPlayerId = 0

io.on('connection', function (socket) {

    // send list of rooms at connect
    socket.emit("connected", {rooms: this.rooms});
    socket.id = ++lastPlayerId;

    // Room
    socket.on('createRoom', (roomName) => {
        const room = {
            id: ++lastRoomId,
            name: roomName,
            players: [],
        }
        this.rooms.push(room);
        socket.emit("roomCreated", room);
        socket.broadcast.emit("update_rooms", {rooms: this.rooms});
    });

    socket.on('joinRoom', (id) => {
        const index = this.rooms.map(room => room.id).indexOf(id);
        if (index >= 0) {
            this.rooms[index].players.push(socket.id);
            socket.emit("roomJoined", this.rooms[index]);

            socket.roomId = id;
            socket.roomChannel = this.rooms[index].name;

            socket.join(socket.roomChannel);

            socket.broadcast.emit("update_rooms", {rooms: this.rooms});
        }
    });


    // Game
    socket.on('cardSelected', (cardInfo) => {
        console.log("broadcasting to", socket.roomChannel);
        console.log("socket room", socket.rooms);

        var clients = io.sockets.adapter.rooms[socket.roomChannel].sockets;
       // Shows that the clients ARE in the room
       // returns "{ '1': true, '2': true }" if I have two clients
        console.log(clients); 

        // DOESNT WORK!!
        socket.broadcast.to(socket.roomChannel).emit("cardSelected", cardInfo)
        // DOESNT WORK!!
        io.to(socket.roomChannel).emit("cardSelected");

        // Works
        socket.broadcast.emit("cardSelected", cardInfo);
    });
});

我也试过socket.to(socket.roomChannel).emit("cardSelected", cardInfo);（没有广播），没有任何成功

Answer 1

调试socket.io中的代码后，我发现更改套接字的“id”值会破坏所有内容！

我删除了这一行socket.id = ++lastPlayerId;，现在一切正常：）

所以，请记住：永远不要手动更改套接字的ID 。

socket.broadcast.to并未被会议室中的任何客户

1 个答案: