Question

我有一个功能性应用程序，用于在iPhone和Watch之间共享数据（共享文本），我希望即使手表设置在后台也可以使用（当Watch在后台时，将数据从iPhone发送到Watch）。我读了很多关于如何做到这一点，但似乎对我的应用程序没什么好处。请添加代码以使应用程序正常工作。或者给我一些适合这个应用程序的来源。谢谢！

iPhone代码：

    import UIKit
    import WatchConnectivity
    class ViewController: UIViewController, WCSessionDelegate {

    @IBOutlet weak var iPhoneLabel: UILabel!
    var session : WCSession!;

    func session(_ session: WCSession, activationDidCompleteWith activationState: WCSessionActivationState, error: Error?) {

    }

    func sessionDidBecomeInactive(_ session: WCSession) {

    }

    func sessionDidDeactivate(_ session: WCSession) {

    }

    func session(_ session: WCSession, didReceiveMessage message: [String : Any]) {
        let msg = message["b"] as? String;
        self.iPhoneLabel.text = msg;

    }



    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.

        if(WCSession.isSupported()){
            self.session = WCSession.default;
            self.session.delegate = self;
            self.session.activate();
        }
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }


    @IBAction func sendMessage(_ sender: Any) {
         session.sendMessage(["a" : "Hello"], replyHandler: nil, errorHandler: nil);
    }
}

观察代码：

    import WatchKit
    import Foundation
    import WatchConnectivity
    import UIKit

    class InterfaceController: WKInterfaceController, WCSessionDelegate {

    func session(_ session: WCSession, activationDidCompleteWith activationState: WCSessionActivationState, error: Error?) {

    }


    @IBOutlet var WatchLabel: WKInterfaceLabel!
    var session: WCSession!;

    func session(_ session: WCSession, didReceiveMessage message: [String : Any]) {
        //self.label.setText(message["a"]! as? String)


        let msg = message["a"] as? String;
        WatchLabel.setText(msg);
        sendMessage();



    }

    func sendMessage(){
         session.sendMessage(["b":"goodbye"], replyHandler: nil, errorHandler: nil);
    }


    override func awake(withContext context: Any?) {
        super.awake(withContext: context)

        // Configure interface objects here.
    }

    override func willActivate() {
        // This method is called when watch view controller is about to be visible to user
        super.willActivate()

        if(WCSession.isSupported()){
            self.session = WCSession.default;
            self.session.delegate = self;
            self.session.activate();
        }
    }

    override func didDeactivate() {
        // This method is called when watch view controller is no longer visible
        super.didDeactivate()
    }
   }

使用session.updateApplicationContext（）更改方法session.sendMessage（）后，它只能运行一次。有什么建议吗？

iPhone代码：

import UIKit

import WatchConnectivity


class ViewController: UIViewController, WCSessionDelegate {


@IBOutlet weak var iPhoneLabel: UILabel!

var session : WCSession!;



func session(_ session: WCSession, activationDidCompleteWith activationState: WCSessionActivationState, error: Error?) {
}

func sessionDidBecomeInactive(_ session: WCSession) {
}


 func sessionDidDeactivate(_ session: WCSession) {
}




 func session(_ session: WCSession, didReceiveApplicationContext applicationContext: [String : Any]) {



let msg = applicationContext["b"] as? String

//Use this to update the UI instantaneously (otherwise, takes a little while)
DispatchQueue.main.async() {
    self.iPhoneLabel.text = msg;
}

}



override func viewDidLoad() {
super.viewDidLoad()


if(WCSession.isSupported()){
    self.session = WCSession.default;
    self.session.delegate = self;
    self.session.activate();
}
}


override func didReceiveMemoryWarning() {

super.didReceiveMemoryWarning()

}


@IBAction func sendMessage(_ sender: Any) {



let applicationDict = ["a":"Hello"];
do {
    try session.updateApplicationContext(applicationDict)
} catch {
    print("error")
}
}

}

Code fore Watch：

import WatchKit

import Foundation

import WatchConnectivity

import UIKit


class InterfaceController: WKInterfaceController, WCSessionDelegate {


func session(_ session: WCSession, activationDidCompleteWith activationState: WCSessionActivationState, error: Error?) {

}


@IBOutlet var WatchLabel: WKInterfaceLabel!
var session: WCSession!;



func session(_ session: WCSession, didReceiveApplicationContext applicationContext: [String : Any]) {
    print("Watch message received")

    let msg = applicationContext["a"] as? String
    DispatchQueue.main.async() {
        self.WatchLabel.setText(msg);
    }
    sendMessage();
}

func sendMessage(){


    print("Watch send message");
    let applicationDict = ["b":"goodbye"];
    do {
        try session.updateApplicationContext(applicationDict)
    } catch {
        print("error")
    }
}


override func awake(withContext context: Any?) {
    super.awake(withContext: context)

    // Configure interface objects here.
}

override func willActivate() {
    // This method is called when watch view controller is about to be visible to user
    super.willActivate()

    if(WCSession.isSupported()){
        self.session = WCSession.default;
        self.session.delegate = self;
        self.session.activate();
    }
}

override func didDeactivate() {
    // This method is called when watch view controller is no longer visible
    super.didDeactivate()
}

}

Answer 1

简而言之，即使Watch应用程序处于后台，您也应该使用updateApplicationContext方法而不是sendMessage来从iPhone应用程序发送数据。有关详细信息，请继续。

如果您查看，则表示如果session.sendMessage应用仅在后台运行，则调用Watch不会唤醒它。

在WatchKit扩展名处于活动状态时调用此方法并运行在后台唤醒相应的iOS应用程序使它可以访问。从您的iOS应用程序调用此方法不会唤醒相应的WatchKit扩展。如果你调用这个方法并且对方无法访问（或者之前无法访问）消息传递），errorHandler块用。执行适当的错误。

它还声明此功能仅在isReachable为true时才有效。

使用sendMessage（：replyHandler：errorHandler :)或sendMessageData（：replyHandler：errorHandler :)方法传输数据到可达的对手。这些方法旨在立即实现 iOS应用和WatchKit扩展之间的通信。该对于这些方法，isReachable属性当前必须为true 成功。

要发送用于更新用户界面的数据，您应该使用updateApplicationContext(_:)方法，documentation

当机会出现时，系统会发送上下文数据目标是在对方醒来时准备好使用数据起来。

要使此方法有效，只需要激活session，不需要它是可以访问的。

如何在背景上分享Watch和iPhone之间的数据

1 个答案: