Question

我尝试使用sqlite3_open命令连接我的服务器！

我的问题......这可能吗？我得到了以下代码......

 // Get the path to the documents directory and append the databaseName
 databaseName = @"AnimalDatabase.sql";
 NSString *serverpath = @"http://localhost/app/";

 databasePath = [serverpath stringByAppendingPathComponent:databaseName];


and then this here

-(void) readAnimalsFromDatabase {
 // Setup the database object
 sqlite3 *database;

 // Init the animals Array
 animals = [[NSMutableArray alloc] init];

 // Open the database from the users filessytem
 if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {
  // Setup the SQL Statement and compile it for faster access
  const char *sqlStatement = "select * from animals";
  sqlite3_stmt *compiledStatement;
  if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
   // Loop through the results and add them to the feeds array
   while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
    // Read the data from the result row
    NSString *aName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)];
    NSString *aDescription = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)];
    NSString *aImageUrl = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 3)];

    // Create a new animal object with the data from the database
    Animal *animal = [[Animal alloc] initWithName:aName description:aDescription url:aImageUrl];

    // Add the animal object to the animals Array
    [animals addObject:animal];

    [animal release];
   }
  }
  // Release the compiled statement from memory
  sqlite3_finalize(compiledStatement);

 }
 sqlite3_close(database);

}

任何建议??

Answer 1

在哪里可以看到SQLite可以从URL打开数据库？它只能打开文件（或者在内存中创建临时数据库）。

Answer 2

答案只是 NO ，无论如何你的代码中都有很多错误。例如：

databaseName = @"AnimalDatabase.sql";

你从哪里得到这个。 iPhone正在使用sqlite数据库，它与sql文件没有任何共同之处：）

iphone xcode sqlite3_open远程主机

2 个答案: