Question

下面是我的python脚本的一部分，它在Linux系统和日常自动化系统中读取数据。在邮件正文和邮件中打印发送。我的输入文件每天都在变化，如果输入文件包含所有字符串（或）numarical值，它将完美地运行。

如果输入文件在任何行中都有空字符串/值，则会抛出IndexError并停止打印数据。

f = open('INPUTfile')
lines = f.readlines()
count=len(lines)
f.close()

body1="""

"""

z=0

while (z<count):
      test = lines[z]
      hello = test.split(',')
      a = hello[0:1]
      a1 = a[0]
      b = hello[1:2]
      b1 = b[0]
      c = hello[2:3]
      c1 = c[0]
      d = hello[3:4]
      d1 = d[0]
      e = hello[4:5]
      e1 = e[0]
      f = hello[5:6]
      f1 = f[0]
      g = hello[6:7]
      g1 = g[0]
      h = hello[7:8]
      h1 = h[0]
      i = hello[8:9]
      i1 = i[0]
      j = hello[9:10]
      j1 = j[0]
      k = hello[10:11]
      k1 = k[0]
      l = hello[11:12]
      l1 = l[0]
      m = hello[12:13]
      m1 = m[0]


      d1 = float(d[0])
      g1 = float(g[0])
      j1 = float(j[0])
      m1 = float(m[0])

      if all([d1 < 99.00, j1 < 99.00]):
              body1 = body1 + '<tr><td style="font-family:Calibri;"><b>' + a1 + '</b></td><td style="font-family:Calibri;">' + b1 + '</td></td><td style="font-family:Calibri;">' + c1 + '</td></td><td style="font-family:Calibri;color:red">' + str(round(d1,2)) + '</td></td><td style="font-family:Calibri;">' + e1 + '</td><td style="font-family:Calibri;">' + f1 + '</td></td><td style="font-family:Calibri;color:red">' + str(round(g1,2)) + '</td><td style="font-family:Calibri;">' + h1 + '</td><td style="font-family:Calibri;">' + i1 + '</td><td style="font-family:Calibri;">' + str(round(j1,2)) + '</td><td style="font-family:Calibri;">' + k1 + '</td><td style="font-family:Calibri;">' + l1 + '</td><td style="font-family:Calibri;">' + str(round(m1,2)) + '</td></tr>'

  z=z+1

我的inputfile：

APPU1,2004423,2004417,99.9997,2847,2847,100,7600,7599,99.9846,1248,1248,99.9999
APPU2,,,
APPU3,2004333,2004329,99.9998,2848,2848,100,7593,7592,99.9842,1248,1247,99.9999
APPU4,2004020,2004016,99.9998,2849,2847,100,7596,7595,99.9853,1248,1247,99.9999

请建议打印数据的解决方案，即使INPUT文件中的行包含空值。

Answer 1

我不明白在这里使用while循环。

无论如何，你需要的是while循环开始时的if语句。

while (z<count):
      test = lines[z]
      hello = test.split(',')
      if len(hello) < 14: # or whatever number of items required.
          z+=1
          continue
     #rest of your code goes here

如果我是你，我会写这样的代码。

with open('INPUTfile') as f:
    for i, line in enumerate(f):
        hello = line.split(',')
        #rest of the code.

Answer 2

您可以在python中使用try except块。

try:
    <your logic here> or the code
except IndexError:
    pass # If IndexError is encountered, pass the control to the loop and continue from the next line

使用此代码段并检查是否可以解决问题

for line in lines:
    try:
         test = line
              hello = test.split(',')
              a = hello[0:1]
              a1 = a[0]
              b = hello[1:2]
              b1 = b[0]
              c = hello[2:3]
              c1 = c[0]
              d = hello[3:4]
              d1 = d[0]
              e = hello[4:5]
              e1 = e[0]
              f = hello[5:6]
              f1 = f[0]
              g = hello[6:7]
              g1 = g[0]
              h = hello[7:8]
              h1 = h[0]
              i = hello[8:9]
              i1 = i[0]
              j = hello[9:10]
              j1 = j[0]
              k = hello[10:11]
              k1 = k[0]
              l = hello[11:12]
              l1 = l[0]
              m = hello[12:13]
              m1 = m[0]


              d1 = float(d[0])
              g1 = float(g[0])
              j1 = float(j[0])
              m1 = float(m[0])
    except IndexError:
        pass

由于输入数据中的空行引起的IndexError

2 个答案: