我看到等待似乎永远不会回来。这是示例代码:
public partial class MainWindow : Window, INotifyPropertyChanged
{
private string _status;
private CancellationTokenSource _cancellationTokenSource;
public MainWindow()
{
InitializeComponent();
_status = "Ready";
DataContext = this;
}
public string Status
{
get { return _status; }
set
{
_status = value;
OnPropertyChanged(nameof(Status));
}
}
private void OnStart(object sender, RoutedEventArgs e)
{
Status = "Running...";
_cancellationTokenSource = new CancellationTokenSource();
StartProcessing();
}
private void OnStop(object sender, RoutedEventArgs e)
{
_cancellationTokenSource.Cancel();
}
private async void StartProcessing()
{
try
{
await new Task(() =>
{
Thread.Sleep(5000);
}, _cancellationTokenSource.Token);
}
catch (TaskCanceledException e)
{
Debug.WriteLine($"Expected: {e.Message}");
}
Status = "Done!";
}
public event PropertyChangedEventHandler PropertyChanged;
protected virtual void OnPropertyChanged(string propertyName)
{
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
}
}
OnStart被调用会发生什么,它将状态设置为"正在运行...",然后调用StartProcessing。五秒钟失效,但我从未看到状态设置为"完成!"
如果我打电话给OnStop,那么任务就会被取消,我会看到"完成!"状态。
我猜我是在创建一个任务以及async / await创建的任务,但它是挂起还是死锁?
这是WPF XAML代码:
<Window x:Class="CancellationSample.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
mc:Ignorable="d"
Title="Cancellation Test" Height="350" Width="525">
<DockPanel LastChildFill="True">
<StackPanel DockPanel.Dock="Top">
<Button Width="70" Margin="5" Click="OnStart">Start</Button>
<Button Width="70" Margin="5" Click="OnStop">Stop</Button>
</StackPanel>
<StatusBar DockPanel.Dock="Bottom">
<StatusBarItem>
<TextBlock Text="{Binding Status}"/>
</StatusBarItem>
</StatusBar>
<Grid></Grid>
</DockPanel>
</Window>
答案 0 :(得分:6)
您正在创建new Task
但未启动它,因此它永远不会完成。而是使用Task.Run和await
。
await Task.Run(() => { });
还要考虑使用Task.Delay而不是Thread.Sleep
,这样就不会阻止当前线程,
答案 1 :(得分:5)
您希望避免在方法上使用async void
。更新StartProcessing
以返回Task
,您还应使用Task.Delay
代替Thread.Sleep
private async Task StartProcessing() {
try {
await Task.Delay(5000, _cancellationTokenSource.Token);
} catch (TaskCanceledException e) {
Debug.WriteLine($"Expected: {e.Message}");
}
Status = "Done!";
}
接下来,如果OnStart
实际上是一个事件处理程序,那么它是允许async void
的一个例外。将OnStart
更新为异步,然后等待现在等待的StartProcessing
private async void OnStart(object sender, RoutedEventArgs e) {
Status = "Running...";
_cancellationTokenSource = new CancellationTokenSource();
await StartProcessing();
}
最后我建议阅读
Async/Await - Best Practices in Asynchronous Programming By Stephen Cleary
更好地了解如何使用async / await