我的代码的高级结构如下所示。这只是复制高级结构的一个例子。: -
import scala.concurrent.Future
class FutureReturnsAValue extends PersonAgeModifier {
def main(args: Array[String]) {
val jhonObj = Person("Jhon", 25)
val punishmentResult = addAgeCurse(jhonObj)
println("The punishment result for Jhonny is " + punishmentResult)
}
def addAgeCurse(person: Person): String = {
val oldAge = person.age
val futureAge = LongProcessingOpForAge(person)
futureAge.onSuccess {
newAge =>
if (newAge = oldAge + 5) {
"screw the kiddo, he aged by 5 years" // somehow return this string
}
else {
"lucky chap, the spell did not affect him" // somehow return this string
}
}
}
}
class PersonAgeModifier {
def LongProcessingOpForAge(person: Person): Future[Int] = {
Future.successful {
person.age + 5
}
}
}
case class Person
(
val name: String,
var age: Int
)
object Person {
def apply(name: String, age: Int) = new Person(name, age)
}
所以我的要求是: - 我需要addAgeCurse()方法中的字符串。现在我知道一些你可能会建议将未来的值LongProcessingOpForAge()传递给main(),但这不是我想要的。
问题:
由于
答案 0 :(得分:0)
也许你要求:
scala> import concurrent._, ExecutionContext.Implicits._
import concurrent._
import ExecutionContext.Implicits._
scala> def f = Future(42)
f: scala.concurrent.Future[Int]
scala> def g = f.map(_ + 1)
g: scala.concurrent.Future[Int]
scala> :pa
// Entering paste mode (ctrl-D to finish)
object Main extends App {
for (i <- g) println(i)
}
// Exiting paste mode, now interpreting.
defined object Main
scala> Main main null
43
这是阻止你回答的简单习惯用语。主线程不会退出,直到它拥有它。使用map
转换未来值。