Question

我想动态地将属性添加到Ruby on Rails对象，以便我可以通过Ajax调用访问它们。我知道我可以通过另一个Ajax调用发送信息，但我更愿意动态添加:first_name和:avatar_url属性。这是我的代码......

def get_info

    comments = []
    allTranslations.each do |trans|

        if trans.comments.exists?
            trans.comments.each do |transComment|

                user = ...
                    class << transComment
                        attr_accessor :first_name
                        attr_accessor :avatar_url
                    end
                transComment.first_name = user.first_name
                transComment.avatar_url = user.avatar.url

                comments.push(transComment)


                puts("trans user comments info")
                transComments.each do |x|

                    puts x['comment']
                    puts x['first_name']
                    puts x.first_name
                    puts x['avatar_url']

                end
            end 
        end
    end

    @ajaxInfo = {
        translationUsers: allTranslations,
        currentUserId: @current_user.id,
        transComments: transComments

    }

    render json: @ajaxInfo

end

在4个打印语句中，只打印puts x.first_name，当我在控制台上记录结果时，没有任何属性添加到对象中。

这是相应的Javascript和Ajax：

 $('.my-translations').click(function(){
    $('#translation').empty();



    getTranslations(id).done(function(data){
        console.log(data)    
        var transUsers = []

        ...

  });
 });

function getTranslations(translationId)   {
    return $.ajax({ 
        type: "GET",
        url: '/get_translations_users',
        data: {
            translationId: translationId
        },
        success: function(result)   {
            return result;
        },
        error: function(err)    {
            console.log(err);
        }
    });
};

任何提示或建议表示赞赏！谢谢:)）

Answer 1

在4个打印语句中，只放置x.first_name打印

这是因为当你调用x ['comment']等时，你在x对象上调用[]方法，我不认为该对象是一个哈希。当你调用.first_name时，你使用动态创建的新attr_accessor;我也想。 avatar_url应该可以工作。

如果你这样做，它是否有效：

  @ajaxInfo = {
    translationUsers: allTranslations,
    currentUserId: @current_user.id,
    transComments: comments

}

Answer 2

我找到了这个很棒的帖子来回答我的问题：How to add new attribute to ActiveRecord

如@CuriousMind private String keywordsList = "soup(s?)(base(s*))? hot(pot(s*))? " + "meat(s*) poultr((y)|(ies)){1} " + "beef(s?) cow(s?) ox(es)? bull(s?) " + "pork(s?) pig(s?) oink " + "mutton(s?) lamb(s?) sheep(s?) " + "chick(en(s)*)? hen(s)* rooster(s)* " + "seafood(s?) sea ocean shellfish fish((e)|(es))? " + "vegetable(s?) vege(s?) green plant(s?) veg(gies)? " + "signature(s?) recommendation(s?) recommend " + "h(i+) hell(o)+ y(o+) h(e)+(y) " + "morning afternoon evening " + "love(ly)? great good thank(s)? amazing excellent brilliant outstanding wonderful awesome okay " + "bad lousy useless stupid brainless fool(ish)? " + "got|get provide(s)* menu(s)* suppl(y|ies){1} offer(s*) " + "(good)?by(e+) leave end stop"; public String getKeywordList(){ String [] keywordsListArray = this.keywordsList.split("\\s"); String result = String.format("%-20s", keywordsListArray[0].replaceAll("[^a-z]", "")); for (int i = 1; i < keywordsListArray.length; i++){ keywordsListArray[i] = keywordsListArray[i].replaceAll("[^a-z]", ""); if (i % 5 == 0){ result += String.format("%n%-20s", keywordsListArray[i]); } else result += String.format("%-20s", keywordsListArray[i]); } return result; }所述，会创建属性，而不是哈希。

我按照@Chris Kerlin的解决方案解决了这个问题

谢谢！

使用Ajax

2 个答案: