Question

我在弄清楚如何从结果中删除具有唯一ID的行时遇到了一些麻烦。

基本上我正在运行此查询：

SELECT 
    date(created) AS created, COUNT(customer_id) AS cnt, customer_id
FROM
    case
WHERE
    customer_id IN (16533 , 7186, 17727, 2442, 2646)
GROUP BY  DATE(`created`)

这将为我提供一个客户每天创建案例的频率列表：

Date        cnt customer_id
2017-06-26  9   17727
2017-06-27  1   17727
2017-05-10  16  16533
2016-06-13  1   7186
2016-10-20  1   7186
2016-10-21  1   7186
2016-10-28  1   7186
...

customer_id 16533只在列表中出现一次，我想将其从结果中删除？

亲切的问候

Answer 1

有点像这样：

SELECT 
    date(created) AS created, COUNT(customer_id) AS cnt, customer_id
FROM
    case
WHERE
    customer_id IN (16533 , 7186, 17727, 2442, 2646)
    AND customer_id not in(
        Select customer_id from case 
        group by customer_id 
        having count(*)=1)
GROUP BY  DATE(`created`)

Answer 2

我有新闻给你。这个查询没有意义：

SELECT date(created) AS created, COUNT(customer_id) AS cnt, customer_id
FROM `case`
WHERE customer_id IN (16533 , 7186, 17727, 2442, 2646)
GROUP BY DATE(`created`);

customer_id 假设有什么价值？它从该日期返回任意customer_id。它是不确定的，可能是那个日期的任何一个。

如果您需要列表，请使用group_concat()：

SELECT date(created) AS created, COUNT(customer_id) AS cnt,
       group_concat(customer_id) as customer_ids
FROM `case`
WHERE customer_id IN (16533 , 7186, 17727, 2442, 2646)
GROUP BY DATE(`created`);

如果您想要消除仅出现一次的客户，请明确这样做：

SELECT date(created) AS created, COUNT(customer_id) AS cnt,
       group_concat(customer_id) as customer_ids
FROM `case` c
WHERE c.customer_id IN (16533, 7186, 17727, 2442, 2646) and
      not exists (select 1 
                  from `case` c2
                  where c2.customer_id = c.customer_id and
                        c2.case_id <> c.case_id  -- or whatever the primary key is
                 )
GROUP BY DATE(`created`);

Answer 3

Select * From (SELECT 
    date(created) AS created, COUNT(customer_id) AS cnt, customer_id
FROM
    case
WHERE
    customer_id IN (16533 , 7186, 17727, 2442, 2646)
GROUP BY  DATE(`created`)) t

Where t.customer_id NOT IN (16533)

Answer 4

如果您要求出现不止一次的客户，请不要在此处使用密钥.....以及按正确的字段进行分组.....

SELECT 
    date(created) AS created, customer_Id, COUNT(*) AS cnt 
FROM
    case
WHERE
    customer_id IN (16533 , 7186, 17727, 2442, 2646)
GROUP BY  DATE(`created`), customer_id
HAVING COUNT(*) >1

如果您只想排除16533，请不要在IN套装中使用它。

从表中删除具有唯一ID的行

4 个答案: