Question

我使用symfony 2.8和sonataAdminBundle，在BackOffice中我喜欢看到两种类型的用户＆＃34;客户端＆＃34;和＃34;通讯员＆＃34; ，这两个用户拥有相同的实体＆＃34;用户＆＃34;我已经通过字段＆＃34;类型＆＃34;区分这两个用户。，我已经像这样创建了AdminClasse：

CorrespondantAdmin

 class CorrespondantAdmin extends AbstractAdmin
  {
      public function createQuery($context = 'list')
       {
          $query = parent::createQuery($context);
          $query->andWhere(
          $query->expr()->eq($query->getRootAliases()[0] . '.type', ':my_param')
     );
         $query->setParameter('my_param', 'correspondant');
       return $query;

      }

     protected function configureListFields(ListMapper $listMapper)

       {
           $listMapper

       ->addIdentifier('nom')
        ->add('prenom')
        ->add('email')
        ->add('civilite')
        ->add('dateInscrit')
        ->add('_action', 'actions', array(
            'actions' => array(
                'show' => array(),
                'edit' => array(),
            )
        ))

         ;

      }

ClientAdmin

 class ClientAdmin extends AbstractAdmin
  {
      public function createQuery($context = 'list')
       {
          $query = parent::createQuery($context);
          $query->andWhere(
          $query->expr()->eq($query->getRootAliases()[0] . '.type', ':my_param')
     );
         $query->setParameter('my_param', 'client');
       return $query;

      }

     protected function configureListFields(ListMapper $listMapper)

       {
           $listMapper

       ->addIdentifier('nom')
        ->add('prenom')
        ->add('email')
        ->add('civilite')
        ->add('dateInscrit')
        ->add('_action', 'actions', array(
            'actions' => array(
                'show' => array(),
                'edit' => array(),
            )
        ))

         ;

      }

Admin.yml

    app.admin.correspondant:
    class: Devagnos\AdminBundle\Admin\CorrespondantAdmin
    tags:
        - { name: sonata.admin, manager_type: orm, group: "Utilisateurs", label: "Mes Correspondants" }
    arguments:
        - ~
        - Devagnos\UserBundle\Entity\User
        - ~
    calls:
        - [ setTranslationDomain, [AdminBundle]]
    public: true

app.admin.client:
    class: Devagnos\AdminBundle\Admin\ClientAdmin
    tags:
        - { name: sonata.admin, manager_type: orm, group: "Utilisateurs", label: "Mes Clients" }
    arguments:
        - ~
        - Devagnos\UserBundle\Entity\User
        - ~
    calls:
        - [ setTranslationDomain, [AdminBundle]]
    public: true

我总是声明上一个服务结果的问题（在本期中，结果始终是＆＃34;客户端＆＃34;在＃34;客户端＆＃34;以及＆＃的视图中34;通讯员＆＃34;

有人可以帮我吗？

Answer 1

你清除缓存了吗？你的Admin.yml格式正确吗？

修改两个管理类可能都有相同的路由。尝试为每个管理员定义自己的路线。在那之后清除缓存。

<强> ClientAdmin

class ClientAdmin extends AbstractAdmin { const ROUTE = 'client-user'; protected $baseRoutePattern = self::ROUTE; protected $baseRouteName = self::ROUTE; ...

<强> CorrespondantAdmin

class CorrespondantAdmin extends AbstractAdmin { const ROUTE = 'correspondant-user'; protected $baseRoutePattern = self::ROUTE; protected $baseRouteName = self::ROUTE; ...

显示用户实体SonataAdminBundle

1 个答案: