Question

我正在尝试通过计数（孩子）和所有主人生，与groupby一起获得laravel的主要孩子。下面是表记录和laravel代码。

父表

String[] command1 = {"bash", "-c", "/archive/scripts/grep.pl /apps/ws/logs/*"};

儿童表

    +-------------+------------+  
    | Id          | Name       |
    +-------------+------------+  
    | 1           | a          |
    +-------------+------------+    
    | 2           | b          |
    +-------------+------------+ 
    | 3           | c          |
    +-------------+------------+

结果如果子节点的主节点ID不是0，则计算子节点中所有相同的父节点并显示所有主节点ID。

    +-------------+------------+  
    | parent_Id   | Code       |
    +-------------+------------+
    | 1           | d1         |
    +-------------+------------+ 
    | 1           | d1         |
    +-------------+------------+    
    | 1           | d1         |
    +-------------+------------+ 
    | 1           | d1         |
    +-------------+------------+    
    | 2           | d2         |
    +-------------+------------+ 
    | 2           | d3         |
    +-------------+------------+

现在我的laravel雄辩如下。

    +-------------+----------------------+ 
    |countparentIds in child| parentName       
    +-------------+----------------------+ 
    | 6                     | a          |
    +-------------+----------------------+  
    | 2                     | b          |
    +-------------+----------------------+  
    | 0                     | c          |
    +-------------+----------------------+

现在我得到结果，父表所有行，并计算具有父ID的子。

Answer 1

尝试 CASE WHEN
喜欢这个

   $ter = DB::table('parents')
    ->leftjoin('child', 'parent.id', '=', 'child.parent_id')
    ->select(array('parent.name as Name', DB::raw('CASE WHEN (child.code= "d1") THEN COUNT(child.parent_id) ELSE 0 END as countparentids')))
    ->orderBy('parent.name')
    ->groupBy('parent.name')
    ->get();

Laravel完全加入了groupby和count

1 个答案: