Question

这是我创建的智能镜像中的天气代码。我正在使用其他人的代码，并在运行应用程序时遇到这两个错误（应用程序工作它只是不显示天气）：

ValueError：无法解码JSON对象

错误：无法解码JSON对象。无法得到天气

def get_weather(self):
    try:

    if latitude is None and longitude is None:
        # get location
        location_req_url = "http://freegeoip.net/json/%s" % self.get_ip()
        r = requests.get(location_req_url)
        location_obj = json.loads(r.text)

        lat = location_obj['latitude']
        lon = location_obj['longitude']

        location2 = "%s, %s" % (location_obj['city'], location_obj['region_code'])

        # get weather
        weather_req_url = "https://api.darksky.net/forecast/%s/%s,%s?lang=%s&units=%s" % (weather_api_token, lat,lon,weather_lang,weather_unit)
    else:
        location2 = ""
        # get weather
        weather_req_url = "https://api.darksky.net/forecast/%s/%s,%s?lang=%s&units=%s" % (weather_api_token, latitude, longitude, weather_lang, weather_unit)

    r = requests.get(weather_req_url)
    weather_obj = json.loads(r.text)

    degree_sign= u'\N{DEGREE SIGN}'
    temperature2 = "%s%s" % (str(int(weather_obj['currently']['temperature'])), degree_sign)
    currently2 = weather_obj['currently']['summary']
    forecast2 = weather_obj["hourly"]["summary"]

    icon_id = weather_obj['currently']['icon']
    icon2 = None

    if icon_id in icon_lookup:
        icon2 = icon_lookup[icon_id]

    if icon2 is not None:
        if self.icon != icon2:
            self.icon = icon2
            image = Image.open(icon2)
            image = image.resize((100, 100), Image.ANTIALIAS)
            image = image.convert('RGB')
            photo = ImageTk.PhotoImage(image)

            self.iconLbl.config(image=photo)
            self.iconLbl.image = photo
    else:
        # remove image
        self.iconLbl.config(image='')

    if self.currently != currently2:
        self.currently = currently2
        self.currentlyLbl.config(text=currently2)
    if self.forecast != forecast2:
        self.forecast = forecast2
        self.forecastLbl.config(text=forecast2)
    if self.temperature != temperature2:
        self.temperature = temperature2
        self.temperatureLbl.config(text=temperature2)
    if self.location != location2:
        if location2 == ", ":
            self.location = "Cannot Pinpoint Location"
            self.locationLbl.config(text="Cannot Pinpoint Location")
        else:
            self.location = location2
            self.locationLbl.config(text=location2)
except Exception as e:
    traceback.print_exc()
    print( "Error: %s. Cannot get weather." % e)

self.after(600000, self.get_weather)

@staticmethod
def convert_kelvin_to_fahrenheit(kelvin_temp):
    return 1.8 * (kelvin_temp - 273) + 32

这是应用中天气小部件的代码。我使用的模块是：

from tkinter import *
import locale
import threading
import time
import requests
import json
import traceback
import feedparser

from PIL import Image, ImageTk
from contextlib import contextmanager

所以这些是正在使用的模块。

Answer 1

好的，经过这么长时间的尝试，我发现即使api令牌打印404意味着它被禁止，它也不会改变输出错误的代码部分：

weather_req_url = "https://api.darksky.net/forecast/%s/%s,%s?lang=%s&units=%s" % (weather_api_token, latitude, longitude, weather_lang, weather_unit)

应该是：

weather_req_url = "%s/%s,%s?lang=%s&units=%s" % (weather_api_token, latitude, longitude, weather_lang, weather_unit)

这是因为我的api密钥应该是一个链接，所以“（https）：//api.darksky.net/forecast/”

所以我把它从weather_req_url

中取出来了

N.B。 https in'（）'因此它不会形成可点击的链接

错误：无法解码JSON对象

1 个答案: