Question

如果字符串或文本包含特定域，例如

，我想跳过并

function updateXDiv(myDate) {
      if (lastZoomDate <= myDate) {
        document.getElementById('x-min').innerHTML = xAxis.scale().domain()[0];
        document.getElementById('x-max').innerHTML = xAxis.scale().domain()[1];
      }
    }

返回0

preg_match()

如果有$var="for see our post visit phyteachers.com |click now"; if(preg_match('(((https?|ftps?)\:\/\/)?((www([0-9]+)?)\.)?.*\.[a-zA-Z0-9](\/)?((?!.*phyteachers\b).*))','$var')==0){ echo "ok"; }或http://phyteachers.com或http://www.phyteachers.com或https://www.phyteachers.com或https://phyteachers.com或www.phyteachers.com，则返回phyteachers.com。< / p>

Answer 1

我的以下模式可能会有所改进，但它应该符合您的目的。

~(?:(?:ht|f)tps?:/{2})?(?:w{3}\d*\.)?(?:phyteachers\.com(*SKIP)(*FAIL)|\S+\.[a-z\d]+/?\S*)~

https://regex101.com/r/iZ9HRQ/6

有关模式组件的正式术语，请参阅演示链接。否则，我会提供非正式的解释......

(?:                 # start optional non-capturing group
    (?:ht|f)tps?    # match http, https, ftp, ftps
    :/{2}           # match colon then two slashes
)?                  # end optional group (none of this HAS to exist)
(?:                 # start optional non-capturing group
    w{3}\d*\.       # match www then zero or more digits, then optiona
)?                  # end optional group
(?:                                # start non-capturing group
    phyteachers\.com(*SKIP)(*FAIL) # abort match if found 
    |                              # or
    \S+\.[a-z\d]+/?\S*             # see the demo, too involved to explain in limited space
)                                  # end non-capturing group

如果正则表达式中存在特定域，如何跳过并说不匹配？

1 个答案: