Question

我有一个jsp页面，其中有一个下载链接。在单击链接时，它调用servlet downloadservlet，它从数据库中提取文件以进行下载。但问题是我发送给servlet的文件的标题包含空格。例如=＆GT;大学服务法。所以该字符串将作为College％20Service％20Act进入servlet，并且无法与数据库匹配。怎么办？

我现在使用jsp文件下载pdf。这里pdf已下载但无法打开。任何人都可以建议对此代码进行任何更改。

download.jsp

<%@page import="java.sql.*,java.io.*"%>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<%
    String connectionURL = "jdbc:oracle:thin:@localhost:1521:xe";
    String title = request.getParameter("title");
    Statement stmt = null;
    Connection con = null;
    Blob b=null;
    try
    {
        String filename = title+".pdf";
        Class.forName("oracle.jdbc.driver.OracleDriver");
        con = DriverManager.getConnection(connectionURL, "shivashukla", "system");
        stmt = con.createStatement();
        String qry = "select * from law where title ='" + title+"'";

        ResultSet rst = stmt.executeQuery(qry);
        if (rst.next())
        {
            b = rst.getBlob(6);
        }
        InputStream in = b.getBinaryStream();
        byte b1[] = new byte[(int) b.length()];
        in.read(b1);
                response.reset();

        //response.setContentType("*.pdf");

        response.setHeader("cache-control", "no-cache");
        //response.setHeader("Content-disposition", "attachment; filename=" + filename);

        response.setContentType("application/pdf");  

response.setHeader("Content-disposition","attachment; filename="+filename);  


    }
    catch (Exception e)
    {
        e.printStackTrace();
    }
%>

jsp page

<body style="background-color: antiquewhite;">
    <%
        try {
            String cat = (String)session.getAttribute("cat");
            String state = (String)session.getAttribute("state");
            Class.forName("oracle.jdbc.driver.OracleDriver");
            Connection con = DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:xe", "shivashukla",
                    "system");
            PreparedStatement ps = con.prepareStatement("select * from law where category=? and state=?");
            ps.setString(1, cat);
            ps.setString(2, state);
            ResultSet rs = ps.executeQuery();
    %>

    <table class="table table-bordered table-responsive table-hover" >
        <tr>
            <th>SECTION</th>
            <th>CATEGORY</th>
            <th>TITLE</th>
            <th>STATE</th>
            <th>YEAR</th>
            <th>PDF</th>
        </tr>
        <%
            while (rs.next()) {
        %>
        <tr>
            <td><%=rs.getString(1)%></td>
            <td><%=rs.getString(2)%></td>
            <td><%=rs.getString(3)%></td>
            <td><%=rs.getString(4)%></td>
            <td><%=rs.getString(5)%></td> 
            <td><a href="downloadservlet?title=<%=rs.getString(3)%>" target="_blank">Download</a>
            </td>
        </tr>
        <%
                }
            } catch (Exception e) {
                System.out.println(e);
            }
        %>
    </table>
</body>

Answer 1

您可以使用java.net.URLDecoder.decode()。

尝试更改：

String fn = req.getParameter("title");

为：

String fn = java.net.URLDecoder.decode(req.getParameter("title"));

如何将字符串发送到具有空格的servlet？

1 个答案: