Question

目前我通过curl命令将信息传递给Web API，如下所示：

val cache = igniteContext.fromCache("partitioned")
val result = cache.filter(_._2.contains("Ignite")).collect()

这将返回API的另一个URL，在那里发布所有信息：

http://example.com/xyz#newjobapi:id=19

我试图通过C #Windows表单复制此过程，用户将在其中输入所需信息，一旦提交，他们应该获得返回的URL。

我已经为用户创建了输入此信息的界面。但我不知道如何将此信息发布到Web API并获取生成的URL

是否有可用于通过Windows Form复制上述curl进程的库？

Answer 1

        HttpWebRequest webRequest;

        string requestParams = ""; //format information you need to pass into that string ('info={ "EmployeeID": [ "1234567", "7654321" ], "Salary": true, "BonusPercentage": 10}');

                webRequest = (HttpWebRequest)WebRequest.Create("http://example.com/xyz/php/api/createjob.php");

                webRequest.Method = "POST";
                webRequest.ContentType = "application/json";

                byte[] byteArray = Encoding.UTF8.GetBytes(requestParams);
                webRequest.ContentLength = byteArray.Length;
                using (Stream requestStream = webRequest.GetRequestStream())
                {
                    requestStream.Write(byteArray, 0, byteArray.Length);
                }

                // Get the response.
                using (WebResponse response = webRequest.GetResponse())
                {
                    using (Stream responseStream = response.GetResponseStream())
                    {
                        StreamReader rdr = new StreamReader(responseStream, Encoding.UTF8);
                        string Json = rdr.ReadToEnd(); // response from server

                    }
                }

从Windows Form C发送发布请求＃

1 个答案: