我知道这是一项简单的任务,但在更改我的代码后它停止工作,我无法取回它!我使用两个函数来压缩和解压缩,即使它实际上做的是“jar”和“unjar”,但这不应该产生巨大的差异
public static void zipit(File[] infiles, JarOutputStream jos) throws Exception
{
zipit(infiles,"", jos);
}
public static void zipit(File[] infiles, String root, JarOutputStream jos) throws Exception
{
byte[] buffer = new byte[4096];
for(int i=0; i<infiles.length; i++)
{
// recursive call for subfolders... temporary
if(infiles[i].isDirectory())
{
zipit(infiles[i].listFiles(), infiles[i].getName() + "/", jos);
continue;
}
// create string with absolute path
String entryfile = root + infiles[i].getName();
JarEntry entry = new JarEntry(entryfile);
zos.putNextEntry(entry);
FileInputStream fis = new FileInputStream(infiles[i]);
int count;
while((count = fis.read(buffer, 0, buffer.length)) != -1)
zos.write(buffer, 0, count);
}
}
public static void unzipit(File zipfile, File outputfolder) throws Exception
{
JarFile jar = new JarFile(zipfile);
for(Enumeration entries = jar.entries(); entries.hasMoreElements(); )
{
JarEntry entry = (JarEntry) entries.nextElement();
File unzipped = new File(outputfolder, entry.getName());
if (entry.isDirectory() && !unzipped.exists())
{
unzipped.mkdirs();
continue;
}
else if (!unzipped.getParentFile().exists())
unzipped.getParentFile().mkdirs();
FileOutputStream fos = new FileOutputStream(unzipped);
InputStream in = jar.getInputStream(entry);
byte[] buffer = new byte[4096];
int count;
while((count = in.read(buffer, 0, buffer.length)) != -1)
fos.write(buffer, 0, count);
fos.close();
}
}
任何帮助/建议?
创建JarFile时出错:
java.util.zip.ZipException: error in opening zip file
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.<init>(ZipFile.java:131)
at java.util.jar.JarFile.<init>(JarFile.java:150)
at java.util.jar.JarFile.<init>(JarFile.java:114)
答案 0 :(得分:3)
不知怎的,我得到了它的工作,显然它与流有关...感谢大家的帮助!
class zipper
{
static byte[] buffer = new byte[4096];
public static void unzip(File zipfile, File outputfolder) throws Exception
{
JarFile zip = new JarFile(zipfile);
Enumeration entries = zip.entries();
while(entries.hasMoreElements())
{
JarEntry entry = (JarEntry) entries.nextElement();
File unzipped = new File(outputfolder,entry.getName());
if (entry.isDirectory() && !unzipped.exists())
{
unzipped.mkdirs();
continue;
}
else if (!unzipped.getParentFile().exists())
unzipped.getParentFile().mkdirs();
InputStream in = zip.getInputStream(entry);
FileOutputStream fos = new FileOutputStream(unzipped);
int count;
while((count = in.read(buffer, 0, buffer.length)) != -1)
fos.write(buffer, 0, count);
// clean up
fos.close();
in.close();
}
}
public static void zip(File[] infiles, JarOutputStream jos) throws Exception
{
zip(infiles,"",jos);
// clean up
jos.flush();
jos.close();
}
public static void zip(File[] infiles, String basefolder, JarOutputStream jos) throws Exception
{
for(int i=0; i<infiles.length; i++)
{
if(infiles[i].isDirectory())
{
// recursive call for directories
zip(infiles[i].listFiles(), infiles[i].getName() + File.separator, jos);
continue;
}
String filepath = basefolder + infiles[i].getName();
JarEntry entry = new JarEntry(filepath);
jos.putNextEntry(entry);
FileInputStream fis = new FileInputStream(infiles[i]); // get stream
int count;
while((count = fis.read(buffer, 0, buffer.length)) != -1)
jos.write(buffer, 0, count);
}
}
}
答案 1 :(得分:1)
我不知道这是不是你的问题,但通常很好的做法是在写完后关闭每个zip条目。
请参阅ZipOutputStream.closeEntry()
。
在您显示的代码中,zip中的最后一个条目不会被关闭。您也不会显示关闭JarOutputStream本身的位置。这可能会导致您创建无效的zip文件,这些文件在使用其他方法回读时会出错。