Question

如何将表名作为变量传递。基本上我想制作e函数，我将使用nodejs将表名作为参数和对象插入mysql数据库中的记录我的功能就像

exports.insertIntoDb = function(tableName,insertObj) {
 connection.query('INSERT INTO administrator SET ?',insertObj, function(error, result, fields) {
    if(error){
        res.json({
            status:false,
            message:'There is some problem with query'
        })
    }
    else{
        res.json({
            status : true,
            data : result,
            message: 'user registered successfully'
          })    
       }
  });
 }

但是我想知道如何在这个查询中传递表名，这是从函数中获取的参数。我在询问语法？我正在使用nodejs-mysql

Answer 1

试试这个：

exports.insertIntoDb = function(tableName,insertObj) {
  connection.query('INSERT INTO ?? SET ?', [ tableName, insertObj ], ...)
};

此处记录：https://github.com/mysqljs/mysql#preparing-queries

Answer 2

内部app.js：

app.put('/updateCell', async function(req, res) {
    console.log("REST: PUT /updateCell");
    let orderInfo = req.body;
    let cellValue = orderInfo.cell;
    let CustomerName = orderInfo.CustomerName;
    let ColumnName = orderInfo.columnName;

    connection.query("UPDATE vehicles SET ?? = ? WHERE order_CustomerName = ?", [columnName, cellValue, customerName],
        function(err, result) {
          if (err) throw err;
        });
        res.send();
});

示例：

//cellValue = "Fluffiest hat of them all";
//customerName = "Jenny Hopkins";
//columnName = "description";

因此，SQL查询将与：

UPDATE order SET description = "fluffiest hat of them all" WHERE order_CustomerName = "Jenny Hopkins";

Nodejs-Mysql查询表名作为变量

2 个答案: