Question

我试图使用（log）函数的返回对象而不去除多个变量

在nodeJS / Javascript最佳做法后，如何做到最好。

我必须多次声明这个变量，因为我知道它是参考。

var configuredRoute;
configuredRoute = router.route('/api/v1/people')
  .get(PersonController.all)
  .post(PersonController.add)

logger.configured(configuredRoute.methods,configuredRoute.path)

configuredRoute = router.route('/api/v1/people/:id')
  .get(PersonController.getOne)
  .put(PersonController.update)
  .delete(PersonController.remove)
logger.configured(configuredRoute.methods,configuredRoute.path)

configuredRoute = router.route('/api/v1/supervisor')
  .get(auth.isAuthenticated(), PersonController.allSupervisors)

logger.configured(configuredRoute.methods,configuredRoute.path)

configuredRoute = router.route('/api/v1/people/status/:phone')
  .get(PersonController.isRegistered)

logger.configured(configuredRoute.methods,configuredRoute.path)

Answer 1

我认为你在询问如何在不声明更多变量的情况下调用logger.configured来配置每条路线的结果。一种解决方案是使用匿名函数来表示路由配置：

//assuming logger and router are declared in this scope

function configureRoute(route) {
    const {methods, path} = route(router)
    logger.configured(methods, path)
}

const routes = [
    router =>
        router.route('/api/v1/people')
            .get(PersonController.all)
            .post(PersonController.add),
    router =>
        router.route('/api/v1/people/:id')
            .get(PersonController.getOne)
            .put(PersonController.update)
            .delete(PersonController.remove),
    router =>
        router.route('/api/v1/supervisor')
            .get(auth.isAuthenticated(), PersonController.allSupervisors),
    router =>
        router.route('/api/v1/people/status/:phone')
            .get(PersonController.isRegistered)
]

for (const route of routes) {
    configureRoute(route)
}

在NodeJS中重用变量

1 个答案: