Question

我有两个Xml文件

main.xml中

<?xml version="1.0" standalone="yes"?>
<NewDataSet>
  <Table>
    <RowNo>1</RowNo>
    <BatchMId>632</BatchMId>
    <RandomNo>513EHGPDX9GH</RandomNo>
    <ParentRandomNo>0000003</ParentRandomNo>
    <Status>6</Status>
    <AggregrationTimestamp>08/06/2017 1:07:28 </AggregrationTimestamp>
    <CommissioningTimestamp>06/06/2017 17:26:31</CommissioningTimestamp>
    <Grade>A</Grade>
  </Table>
  <Table>
    <RowNo>2</RowNo>
    <BatchMId>632</BatchMId>
    <RandomNo>6S91XPK1Y8AV</RandomNo>
    <ParentRandomNo>0000004</ParentRandomNo>
    <Status>6</Status>
    <AggregrationTimestamp>08/06/2017 1:07:28 </AggregrationTimestamp>
    <CommissioningTimestamp>06/06/2017 17:26:31</CommissioningTimestamp>
    <Grade>A</Grade>
  </Table>
</NewDataSet>

Change.xml

<?xml version="1.0" standalone="yes"?>
<NewDataSet>
  <Table>
    <RowNo>1</RowNo>
    <BatchMId>632</BatchMId>
    <RandomNo>513EHGPDX9GH</RandomNo>
    <ParentRandomNo>0000003</ParentRandomNo>
    <Status>5</Status>
    <AggregrationTimestamp>09/06/2017 11:07:28 </AggregrationTimestamp>
    <CommissioningTimestamp>09/06/2017 11:07:28</CommissioningTimestamp>
    <Grade>B</Grade>
  </Table>
</NewDataSet>

在两个文件中<randomno>都是唯一的，两个文件都是相同的。 Change.xml只有一些更新的元素值。

现在我想用这些更改来更新Main.xml，并且需要这样的输出..

<?xml version="1.0" standalone="yes"?>
<NewDataSet>
  <Table>
    <RowNo>1</RowNo>
    <BatchMId>632</BatchMId>
    <RandomNo>513EHGPDX9GH</RandomNo>
    <ParentRandomNo>0000003</ParentRandomNo>
    <Status>5</Status>
    <AggregrationTimestamp>09/06/2017 11:07:28 </AggregrationTimestamp>
    <CommissioningTimestamp>09/06/2017 11:07:28</CommissioningTimestamp>
    <Grade>B</Grade>
  </Table>
  <Table>
    <RowNo>2</RowNo>
    <BatchMId>632</BatchMId>
    <RandomNo>6S91XPK1Y8AV</RandomNo>
    <ParentRandomNo>0000004</ParentRandomNo>
    <Status>6</Status>
    <AggregrationTimestamp>08/06/2017 1:07:28 </AggregrationTimestamp>
    <CommissioningTimestamp>06/06/2017 17:26:31</CommissioningTimestamp>
    <Grade>A</Grade>
  </Table>
</NewDataSet>

我在此文件中至少有500000条记录，我想在不使用c＃中的任何循环的情况下更新此xml文件。如果有人对此有所了解，请告诉我。我尝试使用for循环，但更新它需要更多的时间。所以，如果任何人有一个没有循环的想法，那么与我分享。

Answer 1

请尝试以下获取字典：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication71
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            Dictionary<string, XElement> dict = doc.Descendants("Table").GroupBy(x => (string)x.Element("RandomNo"), y => y).ToDictionary(x => x.Key, y => y.FirstOrDefault());
        }
    }
}

Answer 2

这是你的代码。工作完美。 Source是您的源集，更改位于更改集

DataSet changeSet = new DataSet();
changeSet.ReadXml("d:\\change.xml");
DataSet sourceSet = new DataSet();
sourceSet.ReadXml("d:\\source.xml");
sourceSet.Tables[0].PrimaryKey = new DataColumn[] { sourceSet.Tables[0].Columns["ParentRandomNo"] };
changeSet.Tables[0].PrimaryKey = new DataColumn[] { changeSet.Tables[0].Columns["ParentRandomNo"] };
try
{
    sourceSet.Merge(changeSet, false);
    sourceSet.AcceptChanges();
    sourceSet.WriteXml("d:\\updated.xml");
}
catch (Exception)
{
    throw;
}

使用C＃Without Loops中的另一个XML文件更新XML文件

2 个答案: