Question

所以我有一个目录，用今天的日期创建，用户选择三个整数。在这个目录中，我创建了许多子文件夹，名为ARI，Ale，Cdl，MXF，Reports等等。

我想创建更多子文件夹，但只为一个子文件夹创建'ARI'文件夹。

如何指定我想要创建名为“Main Unit”和“Second Unit”的文件夹？

以下是我到目前为止所做的事情 - 感谢任何帮助:)

#!/Library/Frameworks/Python.framework/Versions/2.7/bin/python2.7
from __future__ import print_function
import os
import datetime


try: #Handle Python 2.7
    input = raw_input
except NameError:
    pass

deepfolders = ("Main Unit", "Second Unit")
subfolders = ("ari", "sound", "cdl" , "mxf" , "h264" , "reports" , "ale")
parent_format = "{0:03d}_{1:%y%m%d}_Unit_Project"
path = ('/Volumes/Macintosh HD/Users/thenightfactory/Documents')
path2 = ('/Volumes/Macintosh HD/Users/thenightfactory/Pictures')
os.chdir(path)

from datetime import datetime

weekday = datetime.strftime(datetime.now(), "%A")

print ("")
print ("Hello, Happy " + weekday + "! Please Select A Shooting Day To Create Today's Folders:")
print ('\033[91m' + "This will only work until midnight and can only be three integers eg. 023" + '\033[0m')
print("=" * 80)

while True:
    try:
        shootnum = (int(input("Enter today's shoot number > ")))
    shootnum = (str(shootnum))
    shootnum = int(shootnum[:3])

    successful= True
    if successful:
        print ("")
        print ('\033[91m' + "Folder's Have Been Created, Good Luck Shooting!" + '\033[0m')
        print ("")
    break
    except ValueError:
        print('\033[91m' + "Invalid number, please try again." + '\033[0m')

import datetime 

parentpath = parent_format.format(shootnum, datetime.datetime.now())
if not os.path.exists(parentpath):
    os.makedirs(parentpath)
    for subfolder in subfolders:
        os.makedirs(os.path.join(parentpath, subfolder))

os.chdir(path2)
parentpath = parent_format.format(shootnum, datetime.datetime.now())
if not os.path.exists(parentpath):
    os.makedirs(parentpath)
    for subfolder in subfolders:
        os.makedirs(os.path.join(parentpath, subfolder))

Answer 1

假设你想要一个（半）通用解决方案，解决问题的一种方法是将所有位加在一起，因为join可以使用多个参数。因此，在'ari'子文件夹中运行时添加一个额外的循环：

deepsubs = ['ari']
if not os.path.exists(parentpath):
    os.makedirs(parentpath)
    for subfolder in subfolders:
        os.makedirs(os.path.join(parentpath, subfolder))
        if subfolder in deepsubs:
            for deepfolder in deepfolders:
                os.makedirs(os.path.join(parentpath, subfolder, deepfolder))

Answer 2

我的方法只是检查子文件夹值并下降到它并创建所需的目录。

parentpath = parent_format.format(shootnum, datetime.datetime.now())
if not os.path.exists(parentpath):
    os.makedirs(parentpath)
    for subfolder in subfolders:
        pwd = os.getcwd()
        os.makedirs(os.path.join(parentpath, subfolder))
        # Checking in list in case you want todo same for multiple dir
        # else just eqality check would do
        if subfolder in ['ari']:
            os.chdir(os.path.join(parentpath, subfolder))
            for df in deepfolders:
                os.makedirs(os.path.join(parentpath, subfolder, df))
            os.chdir(pwd)

如果这不是你想要的，请告诉我。

在特定子文件夹

2 个答案: