Question

该计划的原则是根据足球运动员的表现（进球数）得出最终排名。因此，我必须根据目标的数量来归纳分数。

仅有3名足球运动员，根据目标数量排名从最小到最大。有两轮更多的最终排名。我必须学会操纵数组和函数（不使用函数zip，sort等等）

这是我的数组

name = [＆＃34; Henry＆＃34;，＆＃34; Owen＆＃34;，＆＃34; Drogba＆＃34;] =＆gt;足球运动员的名字

goal1 = [18,12,6] =＆gt;它是关于每个球员在第一轮中的进球数量

goal2 = [6,8,5] =＆gt;这是关于每个球员在第二轮中的进球数量

增益= [2,4,6] =＆gt;根据目标数得分属性如果你标记了大部分目标，你将获得6分。所以最大。

我不知道它是否清楚？对不起我的英语不好。

我的问题，我有另一个数组点= [0,0,0]我怎样才能在这个数组中获得最终排名的总积分？对于每一轮我都希望用当前点加上新的点。

我希望用新功能预览最终排名。非常感谢你。

def printOne(name, goal, title, current_pts):
    print("\t\t\t\t{}\n".format(title))
    for i in range(len(name)):
        print("\t\t\t\t {} \t {} points {} goals".format(name[i], gain[i] ,goal[i]))
    print("=======================================================")
    return current_pts

def sort(name, goal1, goal2, pts):
    swap = True
    while swap:
        swap = False
        for i in range(len(name) - 1):
            if goal1[i + 1] < goal1[i]:
                name[i], name[i + 1] = name[i + 1], name[i]
                goal1[i], goal1[i + 1] = goal1[i + 1], goal1[i]
                goal2[i], goal2[i + 1] = goal2[i + 1], goal2[i]
                pts[i], pts[i + 1] = pts[i + 1], pts[i]
                swap = True
    return name, goal1, goal2, pts

def test(name, goal, pts):
  for i in range(len(name)):
    goalTotal.append(goal1[i] + goal2[i])
    print(name[i] + " \t  ????  points \t   " + str(goalTotal[i]) + " goals : ")

  return name, goal, pts   


name = ["Henry", "Owen", "Drogba"]
point = [0,0,0]
goal1 = [18, 12, 6]
goal2 = [6, 8, 5]
gain = [2,4,6]
goalTotal = []


name, goal1, goal2, point = sort(name, goal1, goal2, point)
point = printOne(name, goal1, "First round", point)

name, goal2, goal1, point = sort(name, goal2, goal1, point)
point = printOne(name, goal2, "Second round", point)

test(name, goalTotal, "Ranking total ")

结果如下

First round
Drogba    2 points 6 buts        
Owen      4 points 8 buts        
Henry     6 points 10 buts     
=======================================================
Second round

Henry     2 points 4 buts     
Drogba    4 points 5 buts     
Owen      6 points 6 buts     
=======================================================
Final Ranking
Drogba    6 points
Henry     8 points
Owen      10 points

Answer 1

我不确定我是否理解正确，但你的意思是这样吗？

import numpy as np
def printOne(name,gain, goal, title, current_pts):
    print("\t\t\t\t{}\n".format(title))
    for i in range(len(name)):
        print("\t\t\t\t {} \t {} points {} buts \t {} total points".format(name[i], gain[i] ,goal[i],current_pts[i]))
    print("=======================================================")
    return current_pts

def trier( goal, pts, gain):
    minIndex = goal.index(min(goal))
    maxIndex = goal.index(max(goal))
    middleIndex = 0
    if minIndex + maxIndex == 2:
        middleIndex = 1
    elif minIndex + maxIndex == 1:
        middleIndex = 2
    gain_per_person = [0,0,0]

    gain_per_person[maxIndex] = gain[2]
    gain_per_person[middleIndex] = gain[1]
    gain_per_person[minIndex] = gain[0]
    pts = np.add(pts, gain_per_person)
    return gain_per_person, pts


name = ["Henry", "Owen", "Drogba"]
point = [0,0,0]
goal1 = [18, 12, 6]
goal2 = [6, 8, 5]
gain = [2,4,6]

gain1, point = trier(goal1, point, gain)
point = printOne(name, gain1, goal1, "First round", point)

gain2, point = trier(goal2, point, gain)
point = printOne(name, gain2, goal2, "Second round", point)

结果如下：

First round

Henry    6 points 18 buts    6 total points
Owen     4 points 12 buts    4 total points
Drogba   2 points 6 buts     2 total points
=======================================================
Second round

Henry    4 points 6 buts     10 total points
Owen     6 points 8 buts     10 total points
Drogba   2 points 5 buts     4 total points
=======================================================

这是你在找什么？

编辑在评论中回答问题
＆＃34;感谢您的帮助。在编写最终结果时，我编辑了我的第一篇文章。你如何在第二轮中添加第二轮的积分？最终排名？＆＃34;

在开始点= [0,0,0]
然后为goal1调用trier方法 trier([18,12,6], [0,0,0], [2,4,6])
goal1 = [6,4,2]的gain_per_person 在pts = np.add(pts, gain_per_person)行，[0,0,0]点和[6,4,2]被添加到彼此，这导致pts为[6,4,2] 然后将其作为第二个返回值返回并保存在point。

中

然后为goal2
调用trier方法 trier([6,8,5], [6,4,2], [2,4,6])
goal1 = [4,6,2]的gain_per_person 在pts = np.add(pts, gain_per_person)行，[4,6,2]点和[6,4,2]被添加到彼此，这导致pts为[10,10,4] 然后将其作为第二个返回值返回并保存在point。

中

编辑2
如果名称是["Henry", "Owen", "Drogba"]
而goal1的结果是[6,4,2]
而目标2的结果是[2,6,4]
那么期望的结果是[8,10,6]

将这个故事放在python代码中

points_goal1 = [6, 4, 2]
points_goal2 = [2, 6, 4]
points_total = [0, 0, 0]

for index in range(3):
    print(index)
    print("points_goal1[", index, "] =", points_goal1[index])
    print("points_goal2[", index, "] =", points_goal2[index])
    print()
    points_total[index] = points_goal1[index] + points_goal2[index]

print("=======================================================")
print("points_goal1 =", points_goal1)
print("points_goal2 =", points_goal2)
print("points_total =", points_total)

结果是

0
points_goal1[ 0 ] = 6
points_goal2[ 0 ] = 2

1
points_goal1[ 1 ] = 4
points_goal2[ 1 ] = 6

2
points_goal1[ 2 ] = 2
points_goal2[ 2 ] = 4

=======================================================
points_goal1 = [6, 4, 2]
points_goal2 = [2, 6, 4]
points_total = [8, 10, 6]

数组中的属性点

1 个答案: