Question

我的项目中有以下结构：

struct templateScheduleResponse: Decodable {
    let templateScheduleTypes: [scheduleTemplateType]
}

struct scheduleTemplateType: Decodable {
    let templateScheduleNames: [templateScheduleName]?
    let templateTypeId: String?
    let templateTypeName: String
}

struct templateScheduleName: Decodable {
    let templateNameId: String?
    let templateSchedName: String
}

我想对它进行排序，以便templateScheduleName数组按templateSchedName值排序。

我完全坚持如何做到这一点。

请指点什么？（我刚刚开始学习Structs，如果你不能告诉我的话！）

谢谢！

更新：这是我的JSON数据：

{
    templateScheduleTypes =     (
                {
            templateScheduleNames =             (
                                {
                    templateNameId = "fad562bc-4510-49ea-b841-37a825a2f835";
                    templateSchedName = "Daily_Intensive";
                },
                                {
                    templateNameId = "fdeeb79f-6321-4ff6-b1f0-8272a018e73b";
                    templateSchedName = "Weekly_Full_Log_Directories";
                },
                                {
                    templateNameId = "84f9800f-da18-44b8-822f-830069dcc594";
                    templateSchedName = "Weekly_Full";
                },
                                {
                    templateNameId = "47a6f050-13d7-4bf6-b5db-ab53e0a3aa54";
                    templateSchedName = "Weekly_Full_Catalog_Two_Weeks";
                },
                                {
                    templateNameId = "b8ef9577-e871-4d79-8d3a-cfe958c0c3aa";
                    templateSchedName = "Weekly_Full_Over_WAN";
                },
                                {
                    templateNameId = "8d507f52-0d74-404e-ad0d-76e6a7a94287";
                    templateSchedName = "Monthly_Full";
                }
            );
            templateTypeId = "4e73b9ea-71d0-4abd-83c6-7d7b6d45641b";
            templateTypeName = datalist;
        },
                {
            templateScheduleNames =             (
                                {
                    templateNameId = "39386552-45a5-4470-b152-7be00583e767";
                    templateSchedName = "Scheduled_Exchange_Server";
                }
            );
            templateTypeId = "a7c28240-c187-4f86-818c-efd86fb26c7d";
            templateTypeName = MSESE;
        },
                {
            templateScheduleNames =             (
                                {
                    templateNameId = "0037846c-d1fe-4c8f-8eec-c62681a12a57";
                    templateSchedName = "Scheduled_Exchange_Single_Mailbox";
                }
            );
            templateTypeId = "9e06f06a-11dc-44b8-97a0-68bd0b45a07a";
            templateTypeName = Mailbox;
        }
    );
}

Answer 1

您可以进行临时排序，而无需遵守Comparable。如果x是templateScheduleType类型的某个变量：

x.templateScheduleNames.sorted(by: { (lhs, rhs) -> Bool in
    return lhs.templateSchedName < rhs.templateSchedName
})

如果要确保数组在构造时就地排序，请在scheduleTemplateType上定义一个init方法，就像在类上一样：

init(scheduleNames: [templateScheduleName], typeID:String?, typeName:String) {
   self.templateScheduleNames = scheduleNames.sorted(by: { (lhs, rhs) -> Bool in
        return lhs.templateSchedName < rhs.templateSchedName
    })
   self.templateTypeId = typeID
   self.templateTypeName = typeName
}

Answer 2

首先，结构名称应以大写字符开头。

要回答您的问题，您需要制作TemplateScheduleName

struct TemplateScheduleName: Decodable {
    let templateNameId: String?
    let templateSchedName: String
}

符合Comparable

extension TemplateScheduleName: Comparable {

    static func ==(lhs: TemplateScheduleName, rhs: TemplateScheduleName) -> Bool {
        return lhs.templateSchedName == rhs.templateSchedName
    }

    public static func <(lhs: TemplateScheduleName, rhs: TemplateScheduleName) -> Bool {
        return lhs.templateSchedName < rhs.templateSchedName
    }
}

现在给出

let list : [TemplateScheduleName] = []

你可以轻松地对其进行排序

let sortedList = list.sorted()

在Swift中使用子结构对结构进行排序

2 个答案: