Question

我有一个运行每个视图的功能来纠正slu .. 例如，如果slug是/ 12-post-about-stuff并且用户输入/ 12-post-abot_stof，则它们将被正确地重定向。问题是不同的视图具有不同的url模式，例如：

/posts/post_slug/
...
/posts/post_slug/comments/new

如何根据当前网址修改slug名称来编写重定向的函数？

编辑：我正在使用board_name和pk参数为每个视图应用装饰器。我不知道的是如何动态返回新网址，因为每个视图的网址格式都不同。

def correct_board_url_name(func):
  def wrapper(request, board_slug):
        try:
            pk = int(board_slug.split('-')[0])
            board = Board.objects.get(pk=pk)
            if (board.slug != board_slug):
                # This does not always work depending on what is entered
                return redirect(request.get_full_path().replace(board_slug, board.slug, 1))
            else:
                return func(request, board_slug)
        except:
            raise Http404('')
    return wrapper

Answer 1

如果您想在许多不同的视图中处理请求，中间件是一个不错的选择。

class RedirectMiddleware(object):
    def process_request(self, request):
        if request.resolver_match.app_name == 'posts' \
                and 'post_slug' in request.resolver_match.kwargs: 
            new_path = None
            # your logic here
            if new_path:
                return redirect(new_path, permanent=True)
        return

在设置中：

MIDDLEWARE = [
    # another middlewares here ...
    'path.to.RedirectMiddleware',
]

Django：如果slug错误，重定向url

1 个答案: