如何在Framer中重新启动SpeechRecognition函数?

时间:2017-07-30 13:41:50

标签: javascript coffeescript framerjs

我想在Framer(coffeescript)中构建一个函数,在那里我可以说一个特定的单词作为语音输入而且会发生一些事情。例如,我说“苹果”然后一个矩形变成绿色。如果我说“香蕉”它会变黄。

到目前为止它只工作一次然后我必须刷新原型才能记录一个新单词。我怎样才能使它流利,所以我可以说更多的话,总是改变颜色?

这是我目前的代码。我使用Google Chrome API进行语音识别,因此原型本身只有在Chrome浏览器中打开时才有效。

SpeechRecognition = window.SpeechRecognition or 
window.webkitSpeechRecognition
recognizer = new SpeechRecognition
recognizer.lang = 'de-DE'

recognizer.continuous = true
recognizer.interimResults = true

recognizer.start()

recognizer.onresult = (event) ->
  result = event.results[event.resultIndex]
  if result[0].transcript is "Apfel"
    rect.backgroundColor = "green"
  else if result[0].transcript is "Banane"
    rect.backgroundColor = "yellow"
  return

1 个答案:

答案 0 :(得分:0)

使用带前缀的属性webkitSpeechRecognition()webkitSpeechGrammarList()。只能让引擎识别"red"作为输入语法,尽管result事件不止一次被触发。

var grammar = '#JSGF V1.0; grammar colors; public <color> = aqua | azure | beige | bisque | black | blue | brown | chocolate | coral | crimson | cyan | fuchsia | ghostwhite | gold | goldenrod | gray | green | indigo | ivory | khaki | lavender | lime | linen | magenta | maroon | moccasin | navy | olive | orange | orchid | peru | pink | plum | purple | red | salmon | sienna | silver | snow | tan | teal | thistle | tomato | turquoise | violet | white | yellow ;'
var recognition = new webkitSpeechRecognition();
var speechRecognitionList = new webkitSpeechGrammarList();
speechRecognitionList.addFromString(grammar, 1);
recognition.grammars = speechRecognitionList;
recognition.continuous = true;
recognition.lang = 'en-US';
recognition.interimResults = true;
recognition.maxAlternatives = 0;

var diagnostic = document.querySelector('.output');
var bg = document.querySelector('html');

document.body.onclick = function() {
  recognition.start();
  console.log('Ready to receive a color command.');
}

recognition.onresult = function(event) {
  console.log(event);
  var color = event.results[0][0].transcript;
  diagnostic.textContent = 'Result received: ' + color;
  bg.style.backgroundColor = color;
}
<body>
click
<div class="output">