JavaFX TableView为相同数据添加额外列

时间:2017-07-30 11:31:22

标签: java javafx javafx-2 javafx-tableview

我有一个小应用程序。有了这个应用程序,我可以将新的Employee记录添加到MySQL数据库,然后显示这些记录。 buildData()从数据库中检索数据并将其显示在TableView中,每次添加新记录以“刷新”TableView时,我也会调用此方法。然而,这并不像预期的那样。

这是添加第一条记录后的视图:

enter image description here

当我按下按钮添加另一条记录时,这就是我得到的:

enter image description here

如果我关闭应用并重新打开它,TableView是正常的:

enter image description here

这就是buildData()方法的样子(Method忽略了Typechecking以及所有这些。可能是原因?)

private ObservableList<ObservableList> data;

public void buildData() {
    Connection c;
    TableColumn col;
    data = FXCollections.observableArrayList();
    try {

        c = DataBaseConnection.connectToDatabase();
        String SQL = "SELECT * FROM employees";

        ResultSet rs = c.createStatement().executeQuery(SQL);

        for (int i = 0; i < rs.getMetaData().getColumnCount(); i++) {

            final int j = i;
            col = new TableColumn(rs.getMetaData().getColumnName(i + 1));
            col.setCellValueFactory(new Callback<TableColumn.CellDataFeatures<ObservableList, String>, ObservableValue<String>>() {
                public ObservableValue<String> call(TableColumn.CellDataFeatures<ObservableList, String> param) {
                    return new SimpleStringProperty(param.getValue().get(j).toString());
                }
            });
            employeeTableView.getColumns().addAll(col);
        }
        while (rs.next()) {

            ObservableList<String> row = FXCollections.observableArrayList();
            for (int i = 1; i <= rs.getMetaData().getColumnCount(); i++) {
                row.add(rs.getString(i));
            }
            data.add(row);
        }
        employeeTableView.setItems(data);

    } catch (Exception e) {
        e.printStackTrace();
        System.out.println("Error on Building Data");
    }
}

然后将新的员工记录添加到数据库中的方法:

 public void addEmployeeToDatabase() {

    Employee employee = new Employee("Anne Droid", "Marketing", "Gender");

    String query = "INSERT INTO employees (Employee_Name, Department, Gender) VALUES (?, ? , ?)";

    try {
        preparedStatement = connection.prepareStatement(query);

        preparedStatement.setString(1, employee.getEmployeeName());
        preparedStatement.setString(2, employee.getDepartment());
        preparedStatement.setString(3, employee.getGender());
        preparedStatement.execute();

        buildData();
        connection.close();

    } catch (SQLException e) {
        e.printStackTrace();
    }
}

最后,Employee类:

public class Employee {

private StringProperty employeeName;
private StringProperty department;
private StringProperty gender;

public Employee() {

}

public Employee(String employeeName, String department, String gender) {
    this.employeeName = new SimpleStringProperty(employeeName);
    this.department = new SimpleStringProperty(department);
    this.gender = new SimpleStringProperty(gender);
}

public String getEmployeeName() {
    return employeeName.get();
}

public StringProperty employeeNameProperty() {
    return employeeName;
}
...

使用纯java,没有FXML。我已经搜索了一个解决方案,但没有一个可用(据我所知)。 有什么指针吗?

1 个答案:

答案 0 :(得分:1)

buildData方法中,您可以替换项目。但是,您可以在TableColumn列表中添加新的columns,而无需删除任何列。这样,每次调用buildData方法时,列数都会增加。

在添加新列之前清除columns列表以解决此问题:

...

ResultSet rs = c.createStatement().executeQuery(SQL);

employeeTableView.getColumns().clear();

for (int i = 0; i < rs.getMetaData().getColumnCount(); i++) {

    final int j = i;
    col = new TableColumn(rs.getMetaData().getColumnName(i + 1));

    ...

    employeeTableView.getColumns().add(col);
}

...