Question

class Employee():
def __init__(self, name, age, salary):
    self.name = name
    self.age = age
    self.salary = salary

def __repr__(self):
    return '({},{},${})'.format(self.name, self.age, self.salary)


from operator import attrgetter

e1 = Employee('Carl', 37, 70000)
e2 = Employee('Kevin', 30, 80000)
e3 = Employee('Rose', 25, 90000)

employees = [e1, e2, e3]

s_employees = sorted[employees, key = attrgetter('age')]

print(s_employees)

我正在通过youtube学习并复制此代码自己尝试，但无法复制结果，我使用Windows系统和Atom编写代码，观看的视频是使用MAC系统和sublime吗它会有所不同吗？

s_employees =已排序[employees，key = attrgetter（＆＃39; age＆＃39;）] ^ SyntaxError：语法无效 [完成0.141秒]

Answer 1

更改为s_employees = sorted(employees, key=attrgetter('age'))

Answer 2

在花哨的public static string Cut = Convert.ToChar(29) + "V" + Convert.ToChar(65) + Convert.ToChar(0);句法糖之前，让我们试试这个：

attrgetter

接下来，您可以将lambda调用替换为：

s_employees = sorted(employees, key = lambda employee: employee.age)

虽然，我也会重写你的from operator import attrgetter s_employees = sorted(employees, key = attrgetter('age'))课程来使用/继承Employee。

collections.namedtuple

sorted（）在Windows系统上获取语法错误

2 个答案: