Question

我不知道这有什么不对，没有错误，但它没有解决更新查询。我不知道它是最新的代码还是旧代码。请告诉我如何解决这个问题。谢谢，这是代码。第一个代码是server.php

这里的结构：

    <?php 

        session_start();

         $username = "";
         $password = "";
         $lastname = "";
         $firstname = "";
         $id = 0;
         $edit_state = false;


        //connect to the database
        $db = mysqli_connect('localhost', 'root', '', 'login');

        // button is clicked
        if (isset($_POST['save'])) {
            $username = $_POST['text_username'];
            $password = $_POST['text_password'];
            $lastname = $_POST['text_lastname'];
            $firstname = $_POST['text_firstname'];
            //adding data in to database
            $query = "INSERT INTO users (username, password, lastname, firstname) values ('$username', '$password', '$lastname', '$firstname')";
            mysqli_query($db, $query);
            $_SESSION['msg'] = "Account Saved!";
            header('location: acc-settings.php');
        }


        //update records in the database
        if (isset($_POST['update'])) {
            $username = mysqli_real_escape_string($_POST['text_username']);
            $password = mysqli_real_escape_string($_POST['password']);
            $lastname = mysqli_real_escape_string($_POST['lastname']);
            $firstname = mysqli_real_escape_string($_POST['firstname']);
            $id = mysqli_real_escape_string($_POST['id']);

            mysqli_query($db, "UPDATE users SET username = '$username', password = '$password', lastname = '$lastname', firstname = '$firstname' where id='$id'");
            $_SESSION['msg'] = "Account Updated!";
            header('location: acc-settings.php');
        }
        //retrieve records
        $results = mysqli_query($db, "SELECT * FROM users"); ?>

这是acc-settings.php

    <?php include 'server.php';

        //fetching the record
        if (isset($_GET['edit'])) {
            $id = $_GET['edit'];

            $rec = mysqli_query($db, "SELECT * FROM users where id=$id");
            $record = mysqli_fetch_array($rec);
            $username = $record['username'];
            $password = $record['password'];
            $lastname = $record['lastname'];
            $firstname = $record['firstname'];
            $id = $record['id'];
        }

             ?>

    <!DOCTYPE html>
    <html>
    <head>
        <title>Account Settings</title>
        <link rel="stylesheet" type="text/css" href="css/acc-style.css">
    </head>
    <body>

            <?php if (isset($_SESSION['msg'])): ?>
            <div class="msg">
                <?php 
                echo $_SESSION['msg']; 
                unset($_SESSION['msg']);
                 ?>
            </div>

            <?php endif ?>
    <table>
        <thead>
            <tr>
                <th>Username</th>
                <th>Password</th>
                <th>Lastname</th>
                <th>Firstname</th>

                <th colspan="2">Action</th>
            </tr>
        </thead>
        <tbody>
            <?php while ($row = mysqli_fetch_array($results)) { ?>
                    <tr>
                    <td><?php echo $row['username']; ?></td>
                    <td><?php echo $row['password']; ?></td>
                    <td><?php echo $row['lastname']; ?></td>
                    <td><?php echo $row['firstname']; ?></td>
                    <td>
                        <a href="acc-settings.php?edit=<?php echo $row['id']; ?>">Edit</a>
                    </td>
                    <td>
                        <a href="#">Delete</a>
                    </td>
                    </tr>
            <?php } ?>



     </tbody>
   </table>
   <form method="post" action="#">
    <input type="hidden" name="text_id" value="<?php echo $id; ?>">
    <div class="input-group">
        <label>Username</label>
        <input type="text" name="text_username" value="<?php echo 
   $username; ?>">
    </div>
    <div class="input-group">
        <label>Password</label>
        <input type="text" name="text_password" value="<?php echo 
    $password; ?>">
    </div>
    <div class="input-group">
        <label>Lastname</label>
        <input type="text" name="text_lastname" value="<?php echo 
    $lastname; ?>">`enter code here`
    </div>
    <div class="input-group">
        <label>Firstname</label>
        <input type="text" name="text_firstname" value="<?php echo 
    $firstname; ?>">
    </div>
    <div class="input-group">
    <?php if ($edit_state == true): ?>
        <button type="submit" name="save" class="btn">Save</button>
    <?php else: ?>
        <button type="submit" name="update" class="btn">Update</button>
    <?php endif ?>
    </div>
 </form>

 </body>
 </html>

请告诉我这段代码有什么问题:(如果问题不明白请评论下来。非常感谢你！

Answer 1

我看到表单输入和$ _POST键的名称不匹配。例如

<input type="hidden" name="text_id" value="<?php echo $id; ?>">

name =＆＃34; text_id＆＃34;，但$ _POST [＆＃39; id＆＃39;]使用，而不是$ _POST [＆＃39; text_id＆＃39;]

许多其他领域也有同样的问题。

在PHP中更新QUERY，没有错误，但它不起作用

1 个答案: