Question

我正在尝试获取id并将其存储在变量中，但它向我显示了变量没有定义，查询因为变量而没有执行，我不明白为什么。

   include 'connect.php';
   if(isset($_GET['OrgName']))
   {
     $file=$_GET['OrgName'];

$sql="SELECT oraganzation.OrgName,oraganzation.City,oraganzation.OrgEmail,oraganzation.OrgPhoneNO, oraganzation.Workfield, oraganzation.Trainingrecruitment, oraganzation.WebsiteLink,Student_comments.comment
 FROM oraganzation , Student_comments
 WHERE oraganzation.OrgName=$file  AND oraganzation.OrgID=Student_comments.OrgID ";  
 }
 $result= mysqli_query($con,$sql) or die ("could not found; ".mysqli_error ($con));

while ($row=mysqli_fetch_array($result) )
 {

  echo "<br><strong> Name : </strong>". $row['OrgName'].
 "<br><strong>
 <br><strong> City : </strong>". $row['City'].
 "<br><strong>
 Email: </strong>" . $row['OrgEmail'].
"<br><strong>
PhoneNO: </strong>". $row['OrgPhoneNO'].
 "<br> <strong>
Work field: </strong> " . $row['Workfield'].
"<br><strong>
Training recruitment:</strong> " . $row['Trainingrecruitment'].
"<br> <strong>
Website Link: </strong> " . $row['WebsiteLink'].
 "<br> <strong>
Comments: </strong> "  .$row['comment']. "<br>" ;

  }

这是我上一页的代码，我把一个href用于获取名称

    $sql="SELECT OrgName, City, OrgEmail, OrgPhoneNO, Workfield, Trainingrecruitment, WebsiteLink,OrgID
  FROM oraganzation";

 $result= mysqli_query($con,$sql) or die ("could not found; ".mysqli_error($con));

 while ($row=mysqli_fetch_array($result) )
 {

?>

 <div class="content "> 
<a href="training.php?name=<?php echo $row['OrgName'] ?> "><?php echo $row['OrgName'] ;?> </a>

        <?php
echo "<br><strong> City : </strong>". $row['City'].
    "<br><strong>
   Email: </strong>" . $row['OrgEmail'].
   "<br><strong>
   PhoneNO: </strong>". $row['OrgPhoneNO'].
  "<br> <strong>
   Work field: </strong> " . $row['Workfield'].
 "<br><strong>
 Training recruitment:</strong> " . $row['Trainingrecruitment'].
  "<br> <strong>
   Website Link: </strong> " . $row['WebsiteLink']. 


    "</div> ";} ?>

Answer 1

$ sql仅在

时定义

if(isset($_GET['OrgName']))

你应该在$ sql之后移动结束括号，运行查询后，或者即使没有设置OrgName也要定义$ sql

未定义的变量：第17行的C：\ xampp \ htdocs \ training.php中的sql

1 个答案: