Question

在我的代码中

for(int i=1; i<submenuCap.toString().length();i++){
     String[] parts = captionRes.getString(i).split("[*]");
     String part1 = parts[0]; 
     String part2 = parts[1];
    System.out.println("First parts: "+part1+" 2nd Part: "+part2);
 }

我的submenuCap.toString.length()中有30个，有些值类似于""，"LOTO Equipment Issue & Return Record*0"和"Some Equipment Issue & Return Record*1"等。

我想只在数据！= ""时拆分，然后根据数据得到0或1的最后一个索引值，但这里我得到的是o / p

 First parts: LOTO Energy Isolation Record 2nd Part: 0
 First parts: LOTO Equipment Issue & Return Record 2nd Part: 0
 First parts: UPS Visitor Entry Record 2nd Part: 0
 First parts: Daily Technical Observation Record 2nd Part: 0
 java.lang.ArrayIndexOutOfBoundsException: 1
 at com.dao.DaoImpl.getMappingCategoryData(DaoImpl.java:240)
 at com.services.ServiceImpl.getMappingCategoryData(ServiceImpl.java:30)
 at com.controller.MasterController.getMappingCategoryData(MasterController.java:71)
 at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
 at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
 at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)

Answer 1

如果split函数返回一个包含至少两个元素的数组，只需添加一个检查。

for(int i=1; i<submenuCap.toString().length();i++){
     String[] parts = captionRes.getString(i).split("[*]");
     if(parts.length >1){ // check added.
        String part1 = parts[0]; 
        String part2 = parts[1];
        System.out.println("First parts: "+part1+" 2nd Part: "+part2);
     }
 }

Answer 2

添加并检查条件

  for(int i=0; i<submenuCap.toString().length();i++){
       if(captionRes.getString(i)!=null&&!captionRes.getString(i).isEmpty()){
          String[] parts = captionRes.getString(i).split("[*]");
          //It would be better checking array size before processing by index
          String part1 = parts[0]; 
          String part2 = parts[1];
          System.out.println("First parts: "+part1+" 2nd Part: "+part2);
      }else{
          //Other logic      
      }
   }

我的字符串变为null然后我得到java.lang.ArrayIndexOutOfBoundsException：1

2 个答案: