Question

我想使用bash脚本取消注释一行。通常我使用perl命令来替换文本，但在这种情况下，这不起作用：

def main():
  # change string to strings accordingly
  number, strings = get_inputs()
  # change result to result in a way similar to
  # the change of `string -> strings` in `get_inputs()`.
  results = [is_palindrome(string) for string in strings]
  for result in results:
      report(result)
  # We could write [report(result) for result in results] here.
  # But we are not interested in the result list
  # The result list will be [None, None, ...].
  # So this is side-effects only.
  # A for loop is usually preferred for side-effects only,
  # and list comprehension for building a list.

提前致谢。

Answer 1

(和)是正则表达式元字符，它们具有特殊含义; they mean to capture what's inside it

/# %wheel ALL=(ALL) NOPASSWD: ALL/与# %wheel ALL=(ALL) NOPASSWD: ALL不匹配。它会匹配# %wheel ALL=ALL NOPASSWD: ALL（请注意缺少parens）并在ALL中捕获$1。

您可以使用\之类的/# %wheel ALL=$ALL$ NOPASSWD: ALL/转义任何特殊元字符，也可以声明在\Q和\E之间按字面意思取消所有内容。 /\Q# %wheel ALL=(ALL) NOPASSWD: ALL\E/

在脚本中取消注释行

1 个答案: