Question

如何将下面的xsd转换为java pojo。我尝试使用eclipse转换它的JAXB项目方式，但它给了我错误（Property "Value" is already defined. Use <jaxb:property> to resolve this conflict.）。我认为这是因为我有名字=“价值”而且它在某处有冲突。

 <xs:complexType name="demo">
    <xs:simpleContent>
      <xs:extension base="xs:string">
        <xs:attribute name="value" type="xs:string" />
      </xs:extension>
    </xs:simpleContent>
  </xs:complexType>

非常感谢帮助！

Answer 1

表示该复杂类型的Java类可能是这样的：

@XmlType(name = "demo")
public class Demo {
    private String valueAttr;
    private String valueContent;

    @XmlAttribute(name = "value")
    public String getValueAttr() {
        return this.valueAttr;
    }

    public void setValueAttr(String valueAttr) {
        this.valueAttr = valueAttr;
    }

    @XmlValue
    public String getValueContent() {
        return this.valueContent;
    }

    public void setValueContent(String valueContent) {
        this.valueContent = valueContent;
    }

}

类名，字段名和方法名可以更改为您想要的名称，因为XML名称在注释中明确给出。

要查看它的工作原理，请使用：

@XmlRootElement
public class Test {

    @XmlElement
    private Demo demo;

    public static void main(String[] args) throws Exception {
        Demo demo = new Demo();
        demo.setValueAttr("this is the attr value");
        demo.setValueContent("this is the element content");
        Test test = new Test();
        test.demo = demo;

        JAXBContext jaxbContext = JAXBContext.newInstance(Test.class);
        Marshaller marshaller = jaxbContext.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
        marshaller.marshal(test, System.out);
    }
}

输出

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<test>
    <demo value="this is the attr value">this is the element content</demo>
</test>

在属性名称=“值”时将xsd转换为java pojo时出现问题

1 个答案: