如何在Classic ASP中阅读excel xml电子表格数据

时间:2017-07-28 10:15:02

标签: xml excel asp-classic spreadsheet

我认为这将是一个简单的xml加载和循环,但出于某种原因,我无法从Excel XML电子表格中读取任何内容。

Excel电子表格的内容似乎是标准化输出,如下所示:

<?mso-application progid="Excel.Sheet"?>
<Workbook
    xmlns="urn:schemas-microsoft-com:office:spreadsheet"
    xmlns:o="urn:schemas-microsoft-com:office:office"
    xmlns:x="urn:schemas-microsoft-com:office:excel"
    xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
    xmlns:html="http://www.w3.org/TR/REC-html40"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt"
    xmlns:user="urn:my-scripts">
    <DocumentProperties
        xmlns="urn:schemas-microsoft-com:office:office">...
    </DocumentProperties>
    <OfficeDocumentSettings
        xmlns="urn:schemas-microsoft-com:office:office">...
    </OfficeDocumentSettings>
    <ExcelWorkbook
        xmlns="urn:schemas-microsoft-com:office:excel">...
    </ExcelWorkbook>
    <Styles>...</Styles>
    <Worksheet ss:Name="Sheet1" ss:Protected="1">
        <Names>
            <NamedRange ss:Name="Print_Titles" ss:RefersTo="=Sheet1!C2,Sheet1!R7"/>
        </Names>
        <Table ss:ExpandedColumnCount="34" ss:ExpandedRowCount="32" x:FullColumns="1" x:FullRows="1" ss:DefaultRowHeight="13.2">
            <Column ss:Hidden="1" ss:Width="175.2"/>
            <Column ss:Width="250.20000000000002"/>
            <Column ss:Width="60" ss:Span="31"/>
            <Row ss:AutoFitHeight="0" ss:Height="150" ss:StyleID="s67">...</Row>
            <Row ss:Height="15">
                <Cell ss:StyleID="s69">
                    <Data ss:Type="String">W89231</Data>
                </Cell>
                <Cell ss:StyleID="s70">
                    <Data ss:Type="String">Tom Brown</Data>
                    <NamedCell ss:Name="Print_Titles"/>
                </Cell>
                <Cell ss:StyleID="s69">
                    <Data ss:Type="String">1E+</Data>
                </Cell>
                <Cell ss:StyleID="s69">
                    <Data ss:Type="String">1m</Data>
                </Cell>

等等

读过byTagName并不是最好的方法,我首先尝试了以下单节点代码:

strFilename = "1B.xml"
Set oXMLDoc = Server.CreateObject("MSXML2.DOMDocument.6.0")
oXMLDoc.async = False
oXMLDoc.Load (Server.MapPath(strFilename))
Set NodeList = oXMLDoc.documentElement.selectNodes("Workbook/Worksheet")
For Each Node In NodeList
 Response.Write Node.selectSingleNode("row/cell/data/text()")
Next

但绝对没有任何反应。

所以我回到了经过试验和信任的byTagName并尝试了以下内容:

strFilename = "1B.xml"
Set oXMLDoc = Server.CreateObject("MSXML2.DOMDocument.6.0")
oXMLDoc.async = False
oXMLDoc.Load (Server.MapPath(strFilename))
Set oRows = oXMLDoc.documentElement.getElementsByTagName("Row")
Response.Write oRows.length

oRows.length反馈为零

即使它是标准的Excel XML电子表格格式,我也似乎无法进入DOM。

如果有人可以解释我如何阅读行并提取必要的数据值,我真的很感激。

此致

汤姆

1 个答案:

答案 0 :(得分:2)

管理以发现它完全与名称空间有关。

添加以下行:

String key;
String value2;
String value3;
while(!toVisit.isEmpty()) {
    key = someQueue.poll()
    value2 = getTitle(key)
    value3 = getSize(value2)
    jedis.hmset(key, value2Map)
    jedis.hmset(key, value3Map)
...

然后我可以在xml中引用标签,如下所示:

Set oXMLDoc = Server.CreateObject("MSXML2.DOMDocument.6.0")
 oXMLDoc.setProperty "SelectionLanguage", "XPath"
 oXMLDoc.setProperty "SelectionNamespaces", "xmlns:myns='urn:schemas-microsoft-com:office:spreadsheet' xmlns:o='urn:schemas-microsoft-com:office:office' xmlns:x='urn:schemas-microsoft-com:office:excel' xmlns:ss='urn:schemas-microsoft-com:office:spreadsheet' xmlns:html='http://www.w3.org/TR/REC-html40' xmlns:msxsl='urn:schemas-microsoft-com:xslt' xmlns:user='urn:my-scripts'"

然后可以开始XML解析! :0)

此致

汤姆