Question

斐波纳契很不错：

  f:|+\
5 f\1 1

但是我没有找到帕斯卡尔三角的类似表达方式。这是我能得到的最好的：

q){x+\\x#1}6
1 1 1  1  1   1  
1 2 3  4  5   6  
1 3 6  10 15  21 
1 4 10 20 35  56 
1 5 15 35 70  126
1 6 21 56 126 252
1 7 28 84 210 462

Answer 1

q idioms page

上有一个非常漂亮的

    An exception of type HttpErrorResponseException was handled in ErrorHandler.Amazon.Runtime.Internal.HttpErrorResponseException: The remote server returned an error: (503) Server Unavailable. ---> System.Net.WebException: The remote server returned an error: (503) Server Unavailable.
   at System.Net.HttpWebRequest.GetResponse()
   at Amazon.Runtime.Internal.HttpRequest.GetResponse() in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\HttpHandler\_bcl\HttpWebRequestFactory.cs:line 106
   --- End of inner exception stack trace ---
   at Amazon.Runtime.Internal.HttpRequest.GetResponse() in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\HttpHandler\_bcl\HttpWebRequestFactory.cs:line 114
   at Amazon.Runtime.Internal.HttpHandler`1.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\HttpHandler\HttpHandler.cs:line 85
   at Amazon.Runtime.Internal.PipelineHandler.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\PipelineHandler.cs:line 55
   at Amazon.Runtime.Internal.Unmarshaller.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\Handlers\Unmarshaller.cs:line 48
   at Amazon.Runtime.Internal.PipelineHandler.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\PipelineHandler.cs:line 55
   at Amazon.SQS.Internal.ValidationResponseHandler.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Services\SQS\Custom\Internal\ValidationResponseHandler.cs:line 28
   at Amazon.Runtime.Internal.PipelineHandler.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\PipelineHandler.cs:line 55
   at Amazon.Runtime.Internal.ErrorHandler.InvokeSync(IExecutionContext executionContext) in E:\JenkinsWorkspaces\v3-trebuchet-release\AWSDotNetPublic\sdk\src\Core\Amazon.Runtime\Pipeline\ErrorHandler\ErrorHandler.cs:line 72

Answer 2

与现代教科书版本相比，original Pascal triangle确实旋转了45°，因此OP的解决方案是正确的，但可以提高其可读性：

q)sums\[6;6#1]
1 1 1  1  1   1
1 2 3  4  5   6
1 3 6  10 15  21
1 4 10 20 35  56
1 5 15 35 70  126
1 6 21 56 126 252
1 7 28 84 210 462

对于那些喜欢破译混淆q代码的人来说，这是一个没有lambda的解决方案：

q)p:(sums\).(-1+;#[;1])@\:
q)p 3
1 1 1
1 2 3
1 3 6

Answer 3

基于code.kx http://code.kx.com/q/ref/adverbs/

上的斐波纳契示例，提出了一个解决方案

q)pascal:{{((+':)x),1}/[x;1]}
q)pascal 0
1
q)pascal 6
1 6 15 20 15 6 1

q){{((+':)x),1}\[x;1]}  7
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1

帕斯卡的三角形，单位为k / q

3 个答案: