是否可以使用JMeter生成UUID v1？

Question

我阅读了JMeter的手册，发现JMeter有__uuid（）函数。它允许为JMeter测试生成UUID类型4。是否可以在JMeter中生成UUIDv1，或者可能存在一些插件。

Answer 1

在jmeter中你可以添加JSR 223 Sampler选择Java语言并为UUID版本1执行java代码：

 String timeuuid = com.datastax.driver.core.utils.UUIDs.timeBased().toString();

然后将其添加到Jmeter变量：

 vars.put("myUUID", timeuuid);

Answer 2

我建议采取以下步骤：

1. 下载Jug library（例如从here下载）并将.jar放到某处JMeter Classpath
2. 重新启动JMeter以选择.jar up

3. 完成后，您应该能够使用JSR223 Test Elements和Groovy language生成UUIDv1，如：

   import com.fasterxml.uuid.EthernetAddress
   import com.fasterxml.uuid.Generators
   import com.fasterxml.uuid.impl.TimeBasedGenerator
   
   def addr = EthernetAddress.fromInterface()
   def gen = Generators.timeBasedGenerator(addr)
   def v1uuid = gen.generate()
   
   log.info(v1uuid.toString())
   

演示：



参考文献：

• Generating version 1 UUIDs
• Groovy is the New Black

Answer 3

首先，我们将生成64个最低和最高有效位作为长值：

private static long get64LeastSignificantBitsForVersion1() {
    Random random = new Random();
    long random63BitLong = random.nextLong() & 0x3FFFFFFFFFFFFFFFL;
    long variant3BitFlag = 0x8000000000000000L;
    return random63BitLong + variant3BitFlag;
}
 
private static long get64MostSignificantBitsForVersion1() {
    LocalDateTime start = LocalDateTime.of(1582, 10, 15, 0, 0, 0);
    Duration duration = Duration.between(start, LocalDateTime.now());
    long seconds = duration.getSeconds();
    long nanos = duration.getNano();
    long timeForUuidIn100Nanos = seconds * 10000000 + nanos * 100;
    long least12SignificatBitOfTime = (timeForUuidIn100Nanos & 0x000000000000FFFFL) >> 4;
    long version = 1 << 12;
    return 
      (timeForUuidIn100Nanos & 0xFFFFFFFFFFFF0000L) + version + least12SignificatBitOfTime;
}

然后我们可以将这两个值传递给UUID的构造函数：

public static UUID generateType1UUID() {
 
    long most64SigBits = get64MostSignificantBitsForVersion1();
    long least64SigBits = get64LeastSignificantBitsForVersion1();
 
    return new UUID(most64SigBits, least64SigBits);
}