Java 1.8,tomcat 8.5,Jersey 2 - 无法使其工作

时间:2017-07-28 06:29:38

标签: java maven tomcat jersey-2.0

我查了所有内容,甚至进行了一些更改,修复了一些问题,但即使tomcat本身启动并运行,服务器仍会发回404。以下是我的所作所为:

的pom.xml:

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>com.resty</groupId>
    <artifactId>resty</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <packaging>war</packaging>
    <repositories>
        <repository>
            <id>maven2-repository.java.net</id>
            <name>Java.net Repository for Maven</name>
            <url>http://download.java.net/maven/2/</url>
            <layout>default</layout>
        </repository>
    </repositories>
    <dependencies>
        <!-- JAX-RS -->
        <dependency>
            <groupId>javax.ws.rs</groupId>
            <artifactId>javax.ws.rs-api</artifactId>
            <version>2.0.1</version>
        </dependency>       
        <dependency>
            <groupId>org.glassfish.jersey.containers</groupId>
            <artifactId>jersey-container-servlet</artifactId>
            <version>2.25.1</version>
        </dependency>
        <dependency>
            <groupId>org.glassfish.jersey.core</groupId>
            <artifactId>jersey-server</artifactId>
            <version>2.25.1</version>
        </dependency>
        <dependency>
            <groupId>org.glassfish.jersey.core</groupId>
            <artifactId>jersey-client</artifactId>
            <version>2.25.1</version>
        </dependency>
    </dependencies>
    <build>
        <finalName>resty</finalName>
        <plugins>
            <plugin>
                  <artifactId>maven-war-plugin</artifactId>
                  <version>3.0.0</version>
            </plugin>
            <plugin>
                <artifactId>maven-compiler-plugin</artifactId>
                <configuration>
                    <source>1.8</source>
                    <target>1.8</target>
                </configuration>
            </plugin>
        </plugins>
    </build>
</project>

的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">
    <display-name>resty</display-name>
    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
        <welcome-file>index.htm</welcome-file>
        <welcome-file>index.jsp</welcome-file>
        <welcome-file>default.html</welcome-file>
        <welcome-file>default.htm</welcome-file>
        <welcome-file>default.jsp</welcome-file>
    </welcome-file-list>

    <servlet>
        <servlet-name>jersey-serlvet</servlet-name>
        <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
        <init-param>
             <param-name>jersey.config.server.provider.packages</param-name>
             <param-value>com.resty</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>jersey-serlvet</servlet-name>
        <url-pattern>/resty/*</url-pattern>
    </servlet-mapping>

</web-app>

Resty.java

package com.resty;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

@Path("/resty")
public class Resty {

    @GET
    @Produces(MediaType.APPLICATION_JSON)
    @Path("/example")
    public String getExample() {
        return "{\"result\":\"blah\"}";
    }
}

我确定我错过了一些东西,但我无法弄清楚它是什么。当在服务器上运行时,eclipse打开这个URL:http://localhost:9090/Resty/但我看到404.我尝试添加更多resty /到url和/ example(参见上面的代码),但都给出了404。

我错过了什么?

1 个答案:

答案 0 :(得分:0)

您在<url-pattern>/resty/*</url-pattern>中使用web.xml并在课堂上使用@Path("/resty")进行类映射,并使用错误的网址http://localhost:9090/Resty/。你需要使用<url-pattern>/*</url-pattern>。和网址将为http://localhost:9090/resty/

您也可以将任何内容用于<url-pattern>/*</url-pattern>,但您需要在url中的控制器路径之前使用此模式。