Question

如果我有一个单元格数组C：

C =  {'name'  'hh' '23' []     []
    'last'  'bb' '12' '8'    'hello'
    'In'    'kk' '12' '2131' []
    'name'  'kk' '23' []     []
    'name'  'cv' '22' []     []
    'name'  'ph' '23' []     [] } ;

如何获取第一列中＆＃39; name＆＃39; 的所有行的行索引以及＆＃39; 23＆＃39; 在第三栏？

indexresult = [1,4,6]

Answer 1

最简单的方法（兼容所有版本）就是使用strcmp，它可以接受单元格数组并进行＆＃34;字符串比较＆＃34;

单线

indexresult = find(strcmp(C(:,1), 'name') & strcmp(C(:,3), '23'));
% indexresult = [1; 4; 6];

<强>解释

% Get logical array of rows where first column is 'name'
logicalname = strcmp(C(:,1), 'name');
% Get logical array of rows where third column is '23'
logical23 = strcmp(C(:,3), '23');
% Get logical array where both of the above are true, using and (&)
logicalname23 = strcmp(C(:,1), 'name') & strcmp(C(:,3), '23');
% Get indices from logical array using find
indexresult = find(strcmp(C(:,1), 'name') & strcmp(C(:,3), '23'));
% If you wanted a row vector instead of column vector, just transpose too
indexresult = find(strcmp(C(:,1), 'name') & strcmp(C(:,3), '23')).';

如果您希望不区分大小写（匹配'name', 'NAME', 'Name', ...），请使用strcmpi代替strcmp。

Answer 2

你可以使用 strfind 来获取具有字符串名称的索引，然后使用逻辑索引从获得的索引中获取23个。

C =  {'name'  'hh' '23' []     []
   'last'  'bb' '12' '8'    'hello'
   'In'    'kk' '12' '2131' []
   'name'  'kk' '23' []     []
   'name'  'cv' '22' []     []
   'name'  'ph' '23' []     [] } ;

% find indices of name
idx = strfind(C(:,1), 'name');
idx = find(not(cellfun('isempty', idx)));
% pick 23 from 3rc column

iwant =idx((str2double(C(idx,3))==23))

在单元格数组中查找字符串索引（Matlab）

2 个答案: