Question

使用红移。我有一个包含以下字段的表：

Column:         Type:
department    | varchar             
employee_ID   | varchar           
event         | varchar     
date          | date

一个日期表，只有一个字段并列出所有日期。每个部门都有几个部门有员工。＆＃34;事件＆＃34;字段有两个可能的值：JOIN或LEAVE。加入记录是他们加入公司/部门的日期，LEAVE记录是他们离开公司/部门的日期。它看起来像这样：

department  employee_id event   date
marketing   001         JOIN    6/17/2017
marketing   002         JOIN    6/19/2017
marketing   002         LEAVE   6/20/2017
marketing   001         LEAVE   6/22/2017

我想制作一个每天都列出的表格（同样我也有一张包含所有日期的表格），以及当他们被雇佣时的值为1，当他们不是所有员工时，值为0。这看起来像这样：

date        department  employee_id employed
6/17/2017   marketing   001         1
6/18/2017   marketing   001         1
6/19/2017   marketing   001         1
6/19/2017   marketing   002         1
6/20/2017   marketing   001         1
6/20/2017   marketing   002         1
6/21/2017   marketing   001         1
6/22/2017   marketing   001         1

想我可能需要创建一个具有开始日期并在同一行中保留日期的新表？为此我可以使用case语句和分区来获取第一个和最后一个日期，但不知道从那里去哪里...也许是一个计数表？该查询可能看起来像这样，但仍然无法获得所需的结果：

select
department,
employee_id,
CASE WHEN ROW_NUMBER() OVER (PARTITION BY employee_id ORDER BY date ASC) = 1 THEN date
ELSE NULL
END AS join_date,
CASE WHEN ROW_NUMBER() OVER (PARTITION BY employee_id ORDER BY date DESC) = 1 THEN date
ELSE NULL
END AS leave_date
from table1

Answer 1

您需要在日期表和包含加入和离开日期的表格之间使用CROSS JOIN。

仅限示例数据。您可以使用现有的表格。

CREATE TEMP TABLE dim_date (dt_val)
AS        SELECT '2017-06-16'::date dt_val
UNION ALL SELECT '2017-06-17'::date dt_val
UNION ALL SELECT '2017-06-18'::date dt_val
UNION ALL SELECT '2017-06-19'::date dt_val
UNION ALL SELECT '2017-06-20'::date dt_val
UNION ALL SELECT '2017-06-21'::date dt_val
UNION ALL SELECT '2017-06-22'::date dt_val
UNION ALL SELECT '2017-06-23'::date dt_val
;
CREATE TEMP TABLE empl_event (department, employee_id, event, event_dt)
AS        SELECT 'marketing' department, 1 employee_id, 'JOIN'  event, '2017-06-17'::date event_dt
UNION ALL SELECT 'marketing' department, 2 employee_id, 'JOIN'  event, '2017-06-19'::date event_dt
UNION ALL SELECT 'marketing' department, 2 employee_id, 'LEAVE' event, '2017-06-20'::date event_dt
UNION ALL SELECT 'marketing' department, 1 employee_id, 'LEAVE' event, '2017-06-22'::date event_dt
;

逻辑步骤1：将JOIN和LEAVE事件转换为第1行的日期

CREATE TEMP TABLE empl_period (department, employee_id, join_dt, leave_dt)
AS
SELECT department
      ,employee_id
      ,MAX(CASE WHEN event = 'JOIN'  THEN event_dt ELSE NULL END) join_dt
      ,MAX(CASE WHEN event = 'LEAVE' THEN event_dt ELSE NULL END) leave_dt
FROM empl_event
GROUP BY 1,2
;

逻辑步骤2：使用CROSS JOIN为每个可能的员工日期组合创建一行，如果日期介于employed和join_dt之间，则将leave_dt设置为1。

SELECT emp.department
      ,emp.employee_id
      ,ddt.dt_val
      ,CASE WHEN ddt.dt_val BETWEEN emp.join_dt AND emp.leave_dt THEN 1 ELSE 0 END employed
FROM       empl_period emp
CROSS JOIN dim_date    ddt
ORDER BY 1,2,3
;

输出示例数据

 department | employee_id |   dt_val   | employed
------------+-------------+------------+----------
 marketing  |           1 | 2017-06-16 |        0
 marketing  |           1 | 2017-06-17 |        1
 marketing  |           1 | 2017-06-18 |        1
 marketing  |           1 | 2017-06-19 |        1
 marketing  |           1 | 2017-06-20 |        1
 marketing  |           1 | 2017-06-21 |        1
 marketing  |           1 | 2017-06-22 |        1
 marketing  |           1 | 2017-06-23 |        0
 marketing  |           2 | 2017-06-16 |        0
 marketing  |           2 | 2017-06-17 |        0
 marketing  |           2 | 2017-06-18 |        0
 marketing  |           2 | 2017-06-19 |        1
 marketing  |           2 | 2017-06-20 |        1
 marketing  |           2 | 2017-06-21 |        0
 marketing  |           2 | 2017-06-22 |        0
 marketing  |           2 | 2017-06-23 |        0

Answer 2

您可以使用以下SQL来使用日期和日期

来扩展日期

DECLARE @dateranges TABLE (employee_id VARCHAR(4),
                           department  VARCHAR(20),
                           join_date   DATE,
                           leave_date  DATE)

INSERT @dateranges SELECT employee_id,
                          department,
                          MIN(event_date) join_date,
                          MAX(event_date) leave_date
                     FROM employment
                    GROUP BY employee_id,
                             department;

WITH cte (dt, dept, id, emd) AS
(
   SELECT tbl.join_date AS dt,
          tbl.department AS dept,
          tbl.employee_id AS employee_id,
          1 AS emd
     FROM @dateranges tbl
    UNION ALL
   SELECT DATEADD(DAY, 1, cte.dt) AS dt,
          tbl.department AS dept,
          tbl.employee_id AS employee_id,
          1 AS emp
     FROM cte
    INNER JOIN @dateranges tbl
       ON cte.id = tbl.employee_id
      AND cte.dept = tbl.department
    WHERE cte.dt < tbl.leave_date
)

SELECT dt AS date,
       dept AS department,
       id AS employee_id,
       emd AS employed
  FROM cte
 ORDER BY dt, id

结果：

date    department  employee_id employed
2017-06-17  marketing   001 1
2017-06-18  marketing   001 1
2017-06-19  marketing   001 1
2017-06-19  marketing   002 1
2017-06-20  marketing   001 1
2017-06-20  marketing   002 1
2017-06-21  marketing   001 1
2017-06-22  marketing   001 1

需要创建一个在日期之前填入值的表

2 个答案: