我有一个带对象的JSON数据库。每个属性都具有特定指定值的属性:a,b或c。
[
{
"id": 1,
"category": "a"
},
{
"id": 2,
"category": "b"
},
{
"id": 3,
"category": "c"
},
{
"id": 4,
"category": "a"
},
{
"id": 5,
"category": "a"
},
{
"id": 5,
"category": "b"
}
]
我希望显示如下内容:
共有 6 项:ax 3 ,bx 2 和cx 1 。
我知道我必须使用objectsinmyjsondatabase.length
来获得总数。
我想知道如何获得具有特定值的对象的长度(数量)?
答案 0 :(得分:1)
解决问题的一种方法是使用map-reduce。这是一个快速的解决方案。希望能解决你的问题。
var data = [
{
"id": 1,
"category": "a"
},
{
"id": 2,
"category": "b"
},
{
"id": 3,
"category": "c"
},
{
"id": 4,
"category": "a"
},
{
"id": 5,
"category": "a"
},
{
"id": 5,
"category": "b"
}
];
// First get list of all categories
var categories = data.map(function(x) { return x["category"]; });
// Count no of items in each category
var countByCategories = categories.reduce(function(x, y) {
if (typeof x !== "object") {
var reduced = {};
reduced[x] = 1;
reduced[y] = 1;
return reduced;
}
x[y] = (x[y] || 0) + 1;
return x;
});
// Final build string that you want
var categoryStrings = [];
for (var category in countByCategories) {
categoryStrings.push(category + ' x ' + countByCategories[category]);
}
var msg = 'There is a total of ' + categories.length + ' items: ';
if (categoryStrings.length > 2) {
msg = categoryStrings.slice(0, -1).join(', ');
msg += ' and ' + categoryStrings.slice(-1);
} else {
msg = categoryStrings.join(', ');
}
// print results
console.log(msg);

答案 1 :(得分:0)
定义一个函数:
getCount(character) {
return this.objects.filter(obj => obj.category === character).length;
}
并将其称为:
this.getCount('a');
答案 2 :(得分:-1)
您可以轻松计算具有此特定值的对象
let objects = [
{
"id": 1,
"category": "a"
},
{
"id": 2,
"category": "b"
},
{
"id": 3,
"category": "c"
},
{
"id": 4,
"category": "a"
},
{
"id": 5,
"category": "a"
},
{
"id": 5,
"category": "b"
}
];
var filtered = new Array();
objects.filter(function (t) {
var found = filtered.some(function (el, index) {
if (false == (t.category === el.category)) {
return false;
}
filtered[index].count = filtered[index].count + 1;
return true;
}, filtered);
if (false === found) {
filtered.push({category: t.category, count: 1});
}
}, filtered);
console.log('There is a total of ' + objects.length + ' items: '
+ filtered.map(function (t) {
return t.category + ' x ' + t.count;
})
);