Question

我有string喜欢：

/wiki/Bologna_Central_Station

我正在尝试将其保存在var中，如下所示：

countryLinks = doSelect("Location").siblings('td').find('a').attr(href);

但我只需保存Bologna_Central_Station

Answer 1

只需执行'/wiki/Bologna_Central_Station'.split('/').splice(-1).join()之类的操作即可。这（与其他一些解决方案不同）具有任意数量的斜杠（'/foo/bar/baz/wiki/Bologna_Central_Station'.split('/').splice(-1).join()）

示例：

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var last = '/wiki/Bologna_Central_Station'.split('/').splice(-1).join();
console.log(last);

var last2 = '/foo/bar/baz/wiki/Bologna_Central_Station'.split('/').splice(-1).join();
console.log(last2);

＆＃13;

Answer 2

有几种方法可以做到这一点：

String.replace()会这样做：

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var s = "/wiki/Bologna_Central_Station";
console.log(s.replace("/wiki/",""));

＆＃13;

或者，String.lastIndexOf()和String.substring()是一个可以处理任意数量的/字符的更动态的解决方案：

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var s = "/wiki/Bologna_Central_Station";

// Find the index position of the last "/" in the string
var lastSlash = s.lastIndexOf("/");

// Extract a substring of the original starting at one more than
// the lastSlash position and going to the end of the string
var result = s.substring(lastSlash + 1);

// Get the part you want:
console.log(result);

＆＃13;

或者String.split() Array.length来处理任意数量的斜杠：

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var s = "/wiki/Bologna_Central_Station";

// Split on the "/" char and return an array of the parts
var ary = s.split("/");
console.log(ary);

// Get the last elmeent in the array.
// This ensures that it works no matter how many slashes you have
console.log(ary[ary.length-1]);

＆＃13;

Answer 3

您可以根据/拆分它，它会为您提供一个数组，您可以从中获取所需的值

var countryLinks = doSelect("Location").siblings('td').find('a').attr(href);
countryLinks=countryLinks.split("/")[1];

Answer 4

let pattern = new RegExp('\/wiki\/')

var string = '/wiki/Bologna_Central_Station'

var newString = string.replace(pattern, '')

Answer 5

var segments = "/wiki/Bologna_Central_Station".split('/');
console.log(segments[segments.length - 1]);

Answer 6

您也可以使用简单的RegExp执行此操作，并替换任意数量的/：

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var href = "/wiki/Bologna_Central_Station";
var countryLinks = href.replace(/.*\//g,'');
console.log(countryLinks);

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如何消除部分字符串并保存到变量中？

6 个答案: